Answer:
You save $266. The television costs $2394.
Step-by-step explanation:
10% off the original price is $266. The television is 10% off, meaning the new price is 90% of the original price. Therefore, you can subtract $2660 - $266 or multiply 90% × $2660.
Answer:
The sum of the first six terms is
![32-8+2-0.5+\frac{1}{8}-\frac{1}{32}=25.59](https://tex.z-dn.net/?f=32-8%2B2-0.5%2B%5Cfrac%7B1%7D%7B8%7D-%5Cfrac%7B1%7D%7B32%7D%3D25.59)
Step-by-step explanation:
Given series is 32-8+2-0.5+...
We may write ![{\{32,-8,2,-0.5,...}\}](https://tex.z-dn.net/?f=%7B%5C%7B32%2C-8%2C2%2C-0.5%2C...%7D%5C%7D)
Let ![a_{1}=32,a_{2}=-8,a_{3}=2,a_{4}=-05,...](https://tex.z-dn.net/?f=a_%7B1%7D%3D32%2Ca_%7B2%7D%3D-8%2Ca_%7B3%7D%3D2%2Ca_%7B4%7D%3D-05%2C...)
Common ratio ![r=\frac{a_{2}}{a_{1}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Ba_%7B2%7D%7D%7Ba_%7B1%7D%7D)
![r=\frac{-8}{32}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B-8%7D%7B32%7D)
![r=\frac{-1}{4}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B-1%7D%7B4%7D)
![r=\frac{a_{3}}{a_{2}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Ba_%7B3%7D%7D%7Ba_%7B2%7D%7D)
![r=\frac{2}{-8}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B2%7D%7B-8%7D)
![r=\frac{-1}{4}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B-1%7D%7B4%7D)
Therefore the common ratio is ![r=\frac{-1}{4}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B-1%7D%7B4%7D)
Therefore given sequence is of the form of Geometric sequence
The nth term of the geometric sequence is
![a_{n}=ar^{n-1}](https://tex.z-dn.net/?f=a_%7Bn%7D%3Dar%5E%7Bn-1%7D)
First to find the 5th and 6th term
That is substitute n=5 and n=6 ,a=32 and
in above equation we get
![a_{5}=32(\frac{-1}{4})^{5-1}](https://tex.z-dn.net/?f=a_%7B5%7D%3D32%28%5Cfrac%7B-1%7D%7B4%7D%29%5E%7B5-1%7D)
![a_{5}=32(\frac{-1}{4})^{4}](https://tex.z-dn.net/?f=a_%7B5%7D%3D32%28%5Cfrac%7B-1%7D%7B4%7D%29%5E%7B4%7D)
![a_{5}=32[(\frac{-1}{4})\times (\frac{-1}{4})\times (\frac{-1}{4})\times (\frac{-1}{4})]](https://tex.z-dn.net/?f=a_%7B5%7D%3D32%5B%28%5Cfrac%7B-1%7D%7B4%7D%29%5Ctimes%20%28%5Cfrac%7B-1%7D%7B4%7D%29%5Ctimes%20%28%5Cfrac%7B-1%7D%7B4%7D%29%5Ctimes%20%28%5Cfrac%7B-1%7D%7B4%7D%29%5D)
![=\frac{1}{8}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B8%7D)
Therefore ![a_{5}=\frac{1}{8}](https://tex.z-dn.net/?f=a_%7B5%7D%3D%5Cfrac%7B1%7D%7B8%7D)
![a_{6}=32(\frac{-1}{4})^{6-1}](https://tex.z-dn.net/?f=a_%7B6%7D%3D32%28%5Cfrac%7B-1%7D%7B4%7D%29%5E%7B6-1%7D)
![a_{6}=32(\frac{-1}{4})^{5}](https://tex.z-dn.net/?f=a_%7B6%7D%3D32%28%5Cfrac%7B-1%7D%7B4%7D%29%5E%7B5%7D)
![a_{6}=32[(\frac{-1}{4})\times (\frac{-1}{4})\times (\frac{-1}{4})\times (\frac{-1}{4})\times (\frac{-1}{4})]](https://tex.z-dn.net/?f=a_%7B6%7D%3D32%5B%28%5Cfrac%7B-1%7D%7B4%7D%29%5Ctimes%20%28%5Cfrac%7B-1%7D%7B4%7D%29%5Ctimes%20%28%5Cfrac%7B-1%7D%7B4%7D%29%5Ctimes%20%28%5Cfrac%7B-1%7D%7B4%7D%29%5Ctimes%20%28%5Cfrac%7B-1%7D%7B4%7D%29%5D)
![=\frac{-1}{32}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B-1%7D%7B32%7D)
Therefore ![a_{6}=-\frac{1}{32}](https://tex.z-dn.net/?f=a_%7B6%7D%3D-%5Cfrac%7B1%7D%7B32%7D)
Therefore the sum of the first six terms is
![32-8+2-0.5+\frac{1}{8}-\frac{1}{32}](https://tex.z-dn.net/?f=32-8%2B2-0.5%2B%5Cfrac%7B1%7D%7B8%7D-%5Cfrac%7B1%7D%7B32%7D)
![=25.5+\frac{3}{32}](https://tex.z-dn.net/?f=%3D25.5%2B%5Cfrac%7B3%7D%7B32%7D)
![=\frac{819}{32}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B819%7D%7B32%7D)
![=25.59](https://tex.z-dn.net/?f=%3D25.59)
Therefore the sum of the first six terms is
![32-8+2-0.5+\frac{1}{8}-\frac{1}{32}=25.59](https://tex.z-dn.net/?f=32-8%2B2-0.5%2B%5Cfrac%7B1%7D%7B8%7D-%5Cfrac%7B1%7D%7B32%7D%3D25.59)
Exactly what is your question?
Answer:
<h2>6 : 1</h2>
Step-by-step explanation:
![\dfrac{72}{12}=\dfrac{72:12}{12:12}=\dfrac{6}{1}=6:1](https://tex.z-dn.net/?f=%5Cdfrac%7B72%7D%7B12%7D%3D%5Cdfrac%7B72%3A12%7D%7B12%3A12%7D%3D%5Cdfrac%7B6%7D%7B1%7D%3D6%3A1)
Using it's concept, it is found that the graph has no horizontal asymptote.
<h3>What are the horizontal asymptotes of a function f(x)?</h3>
The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, we have that:
- The function is undefined for x < 0, hence
is undefined.
- For x > 0, the funciton goes to infinity, hence
.
Thus, the graph has no horizontal asymptote.
More can be learned about horizontal asymptotes at brainly.com/question/16948935
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