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sdas [7]
2 years ago
5

A deli sells 44 cups of soup for every 60 sandwiches. At this rate,how many cups of soup will be sold for every 15 sandwiches

Mathematics
2 answers:
Aleks [24]2 years ago
8 0

Answer:   11 cups of soup

<u>Step-by-step explanation:</u>

Set up a proportion with the given information.  Then cross multiply and solve for the unknown value.

\dfrac{44\ cups}{60\ sandwiches}=\dfrac{x}{15\ sandwiches}\\\\\\44(15)=60(x)\\\\\\\dfrac{44(15)}{60}=x\\\\\\11=x

evablogger [386]2 years ago
3 0

Answer:

11 cups of soups will be sold for every 15 sandwiches

Step-by-step explanation:

all you have to do here is just cross multiply

you have 44 cups of soup every 60 sandwiches : 44/60

the we want to know how many soup will be sold for every 15 sandwiches :

n (representing the number we need to find) /15

44/60 = n/15  (cross multiplying meaning we're going to multiply the sides opposite)

44 x 15 = 660

n x 60 = 60n

660 = 60n

now we have to divide 660 by 60

660/60 = n

11 = n

~batmans wife dun dun dun...aka ~serenitybella

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Which point lies on a circle with a radius of 5 units and center at P(6,1)?
ryzh [129]

Answer:

Option B. R(2,4)

Step-by-step explanation:

we know that

If a ordered pair lie on the circle. then the ordered pair must satisfy the equation of the circle

step 1

Find the equation of the circle

we know that

The equation of the circle in center radius form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

where

r is the radius of the circle

(h,k) is the center of the circle

substitute the values

(x-6)^{2}+(y-1)^{2}=5^{2}

(x-6)^{2}+(y-1)^{2}=25

step 2

Verify each case

case A) Q(1, 11)

substitute the value of x=1, y=11 in the equation of the circle and then compare the results

(1-6)^{2}+(11-1)^{2}=25

25+100=25 ------> is not true

therefore

the ordered pair Q not lie on the circle

case B) R(2,4)

substitute the value of x=2, y=4 in the equation of the circle and then compare the results

(2-6)^{2}+(4-1)^{2}=25

16+9=25 ------> is true

therefore

the ordered pair R lie on the circle

case C) S(4,-4)

substitute the value of x=4, y=-4 in the equation of the circle and then compare the results

(4-6)^{2}+(-4-1)^{2}=25

4+25=25 ------> is not true

therefore

the ordered pair S not lie on the circle

case D) T(9,-2)

substitute the value of x=4, y=-4 in the equation of the circle and then compare the results

(9-6)^{2}+(-2-1)^{2}=25

9+9=25 ------> is not true

therefore

the ordered pair T not lie on the circle

7 0
3 years ago
Tickets at a school play cost $4 in advance or $5 at the door. Total ticket sales for an evening production were $440. If no tic
lisov135 [29]
5x=440
×=the number of tickets sold

then you woukd just divide 440÷5=88
88 tickets were sold at the door
4 0
2 years ago
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gayaneshka [121]

5x-2=3x+8


X=5

That's your answer
8 0
2 years ago
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Find the modal class interval.
photoshop1234 [79]

Answer: 24≤ a < 26

Step-by-step explanation:

The modal class interval is the class interval with the highest frequency, the highest frequency from the table is 8 , which belongs to the class interval 24≤ a < 26

4 0
3 years ago
Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
Read 2 more answers
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