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zmey [24]
3 years ago
5

The chart below shows conversion between gallons and fluid Ounces. Conversion Chart Gallons Fluid Ounces 2 256 3 384 4 512 6 Wha

t is the missing value in the table? O 128 O 640 O 768 896​
Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0

Answer:

b

Step-by-step explanation:

between gallons and Fluid Ounces.because The chart below shows the conversion

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Using linked lists or a resizing array; develop a weighted quick-union implementation that removes the restriction on needing th
balu736 [363]

Answer:

Step-by-step explanation:

package net.qiguang.algorithms.C1_Fundamentals.S5_CaseStudyUnionFind;

import java.util.Random;

/**

* 1.5.20 Dynamic growth.

* Using linked lists or a resizing array, develop a weighted quick-union implementation that

* removes the restriction on needing the number of objects ahead of time. Add a method newSite()

* to the API, which returns an int identifier

*/

public class Exercise_1_5_20 {

public static class WeightedQuickUnionUF {

private int[] parent; // parent[i] = parent of i

private int[] size; // size[i] = number of sites in subtree rooted at i

private int count; // number of components

int N; // number of items

public WeightedQuickUnionUF() {

N = 0;

count = 0;

parent = new int[4];

size = new int[4];

}

private void resize(int n) {

int[] parentCopy = new int[n];

int[] sizeCopy = new int[n];

for (int i = 0; i < count; i++) {

parentCopy[i] = parent[i];

sizeCopy[i] = size[i];

}

parent = parentCopy;

size = sizeCopy;

}

public int newSite() {

N++;

if (N == parent.length) resize(N * 2);

parent[N - 1] = N - 1;

size[N - 1] = 1;

return N - 1;

}

public int count() {

return count;

}

public int find(int p) {

// Now with path compression

validate(p);

int root = p;

while (root != parent[root]) {

root = parent[root];

}

while (p != root) {

int next = parent[p];

parent[p] = root;

p = next;

}

return p;

}

// validate that p is a valid index

private void validate(int p) {

if (p < 0 || p >= N) {

throw new IndexOutOfBoundsException("index " + p + " is not between 0 and " + (N - 1));

}

}

public boolean connected(int p, int q) {

return find(p) == find(q);

}

public void union(int p, int q) {

int rootP = find(p);

int rootQ = find(q);

if (rootP == rootQ) {

return;

}

// make smaller root point to larger one

if (size[rootP] < size[rootQ]) {

parent[rootP] = rootQ;

size[rootQ] += size[rootP];

} else {

parent[rootQ] = rootP;

size[rootP] += size[rootQ];

}

count--;

}

}

public static void main(String[] args) {

WeightedQuickUnionUF uf = new WeightedQuickUnionUF();

Random r = new Random();

for (int i = 0; i < 20; i++) {

System.out.printf("\n%2d", uf.newSite());

int p = r.nextInt(i+1);

int q = r.nextInt(i+1);

if (uf.connected(p, q)) continue;

uf.union(p, q);

System.out.printf("%5d-%d", p, q);

uf.union(r.nextInt(i+1), r.nextInt(i+1));

}

}

}

8 0
3 years ago
Simplify the expression: 6 + 3(x + 4)
quester [9]

Answer:

I think its the 3rd one...

3 0
3 years ago
Read 2 more answers
A rectangular athletic field is three times as long as it is wide. If the perimeter of the athletic field is 128 yards, what are
larisa [96]
Length=3x
Width=x
3x+x+3x+x=128
8x=128
Divide both sides by 8
x=16
3(x)
3(16)=58
Width= 16 yards
Length= 58 yards
4 0
3 years ago
In ∆XYZ, m∠X = 152, y = 15, and z = 19. Find side x and the measure of angle Y to the nearest tenth
solong [7]

The measure of the side x is approximately 33 and the measure of angle Y is approximately 12.321°.

<h3>How to find a missing angle in a triangle by law of sine and law of cosine</h3>

In this problem we must apply the law of cosine and the law of sine to determine the angle Y:

<h3>Law of cosine</h3>

x = \sqrt{y^{2}+z^{2}-2\cdot y\cdot z\cdot \cos X}

x = \sqrt{15^{2}+19^{2}-2\cdot (15)\cdot (19)\cdot \cos 152^{\circ}}

x \approx 33

<h3>Law of sine</h3>

\frac{\sin Y}{y} = \frac{\sin X}{x}

Y = \sin^{-1}\left(\frac{y}{x}\cdot \sin X \right)

Y = \sin^{-1}\left(\frac{15}{33}\cdot \sin 152^{\circ} \right)

Y \approx 12.321^{\circ}

The measure of the side x is approximately 33 and the measure of angle Y is approximately 12.321°. \blacksquare

To learn more on triangles, we kindly invite to check this verified question: brainly.com/question/25813512

7 0
2 years ago
What is the common difference of 80,60,45,33.75
GenaCL600 [577]

Answer:

The common difference (or common ratio) = 0.75

Step-by-step explanation:

i) let the first term be a_{1} = 80

ii) let the second term be a_{2}  = a_{1} . r = 80 × r = 60      ∴  r = \frac{60}{80} = 0.75

iii) let the third term be     a_{3}  = a_{2} . r = 60 × r = 45      ∴  r = \frac{45}{60} = 0.75

iv) let the fourth term be   a_{4} = a_{3} . r = 45 × r = 33.75   ∴ r = \frac{33.75}{45} = 0.75

Therefore we can see that the series of numbers are part of a geometric progression and the first term is 80 and the common ratio = 0.75.

4 0
3 years ago
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