Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
Having a look at the graph, we will find that:
For speed: it is increasing along the x-axis
For height: it is increasing along the y-axis
This means that the function is linearly increasing.
Based on this, the correct choice would be:
D. As speed increases, height increases
D for the same reason percents
Take out the gcf (5).
5(x+3)
The inner binomial cannot be factored.
Final answer: 5(x+3)
