OH i know this one! i know this one!!
* grabs my notebook and a pencil and lays on the floor* hm... its
2
4
8
16
32
yay!! lol this was me lol
5x^2+17x+6=0
(5x+2)(x+3)=0
5x+2=0 x+3=0
x=-2/5 x=-3
Cheers,Irys
The answer to this question is false because it cannot still be both negative after you reflect over two positives.
C, I’m pretty sure
Why do I have to write 20 words for this? This is why I’m rambling.


This is a way to factoring trinomials (there exist different equivalent methods).
Multiply the trinomial but the term accompanying
. This is the second line. Then, you could take the square of the
, ant try to create a factor () () that will correspond to the expression in the second line. That is, we want 
In ? we put the corresponding numbers that, if we multiply them we will obtain 42, and if we add them we will obtain 13. This numbers are 6 and 7. Then, we have 
The last step is divide by the number that we multipy in the first step.