Answer:
Since the gene that transmits hemophilia is linked to the X chromosome (
), for a couple to have a hemophiliac daughter, the father must present the disease and the mother must be a carrier. Therefore, the parents' genotypes are
and
, while the daughter and son genotypes are
and XY, respectively
Explanation:
An X-linked recessive gene -as in the case of hemophilia- will only be expressed in males with the affected X chromosome or in females who are homozygous for that gene.
- A healthy man and a carrier woman can have healthy, hemophilic sons, while half of the daughters could be carriers.
- A haemophiliac man and a healthy woman could have healthy sons and carrier daughters.
- <em>A haemophiliac man and a carrier woman (as in the case above) can have healthy sons, while daughters can be carriers or haemophilics.</em>
The cross between the hemophilic father and the carrier mother can be seen in the following diagram:
Alleles
Y
Y
X
X XY
Where the possibility of having a healthy son and at least one daughter with hemophilia is evident.
Learn more:
Sex linked inheritance brainly.com/question/11839068
E) All of the answers are correct.
Ion channels are proteins located in the membrane that allow ions to pass through the channel pore. Ion channels can be classified (by what opens and closes the channels) into few groups:
• Voltage-gated channels-open and close in response to membrane potential
Examples: Voltage-gated proton channels, Voltage-gated sodium channels, Voltage-gated potassium channels
• Ligand-gated (neurotransmitter) or ionotropic receptors (ligand binds to extracellular domain of the receptor
Examples: "nicotinic" Acetylcholine receptor, ionotropic glutamate-gated receptors
• Lipid-gated- lipid molecules bind to the transmembrane domain of the channel
Example: Inward-rectifier potassium channels
• Light-gated channels-like rhodopsin channel that is directly opened by photons
• Mechanosensitive (e.g. stretch, pressure) ion channels.
I can defiantly help if the options are show. :0)