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2 years ago

15

Jane drove 260 miles using 12 gallons of gas. At this rate, how many gallons of gas would she need to drive 286 miles

1 answer:

marusya05 [52]2 years ago

3 0

260/12=21.67 mpg
286/21.67=13.2 gallons of gas needed

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Solve the system of equations Please If you could solve this it would honestly mean so much! Thank you!

Kay [80]

Answer:

(2, 8)

Step-by-step explanation:

There are a couple of different ways to do this, but I am going to use substitution since we already have one of those equations solved for y. If y=3x+2, then we can sub 3x+2 in for y in the other equation:

-3x + 2(3x + 2) = 10 and

-3x + 6x + 4 = 10 and

3x + 4 = 10 and

3x = 6 so

x = 2. Now that we know x = 2, we can sub a 2 in for x in either equation to solve for y:

y = 3x + 2 gives us, with the substitution, y = 3(2) + 2 so y = 8. The solution set is (2, 8)

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3 years ago

What is the value of p <br> 13²=p<br>

solniwko [45]

169 because 13 x 13 = 168

8 0

3 years ago

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Which of the following could be a function with zeros of —3 and 2? А f(x) = (x - 3)(x + 2) B f(x) = (x = 3)(x - 2) © f(x) = (x+3

Zinaida [17]

Answer:

C

Step-by-step explanation:

to find the zeros you look at what value you would fill in for x to make zero, so (x+3) would have a zero of -3 and (x-2) would have a zero of 2

6 0

3 years ago

NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE

tia_tia [17]

Answer:

Q1:

$-5\sqrt{27c^2}$

$-5\sqrt{27}\sqrt{c^2}$

$-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}$

$-5\times3\sqrt{3}\sqrt{c^2}$

$-5\times3\sqrt{3}c$

$-15\sqrt{3}c$

Q2:

$5\sqrt{72}-3\sqrt{32}$

$5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}$

$5\times6\sqrt{2}-3\times4\sqrt{2}$

$30\sqrt{2}-12\sqrt{2}$

$18\sqrt{2}$

Q3:

$\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}$

$\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}$

$6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}$

$16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}$

Q4:

$\sqrt{15n^2}\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}$

$\sqrt{15}\sqrt{10}n^2\sqrt{n}$

$\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{3}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{6}n^2\sqrt{n}$

Q5:

$\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}$

$\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}$

Cancel off $\sqrt{x}$ :

$\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}$

Cancel off $y:$

$\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}$

Cancel off $\sqrt{y} :$

$\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}$

Multiply $\sqrt{5}$ on the numerator and denominator:

$\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}$

$\frac{\sqrt{15}\sqrt{x}}{20}$

5 0

3 years ago

What’s the opposite of negative two

allsm [11]

Answer: The answer is two

Step-by-step explanation: If you look for opposites of a number its either negative or positive. So when the answer is negative, the opposite is positive and if the answer is positive, the opposite is negative.

8 0

3 years ago

Read 2 more answers