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LuckyWell [14K]
3 years ago
15

The sides of ADEF are d, e, and f. If the lengths of d = 12 and e = 19, what are the

Mathematics
1 answer:
Paraphin [41]3 years ago
6 0

Answer:

The possible range of values for F are from 8 to 30

Step-by-step explanation:

Here, we have a triangle DEF and we want to get the possible lengths of the third side

To evaluate the possible lengths of the third side , we need to follow a rule

The rule is that, for the third side, the sum of the two other sides must be greater than it

This means that the length should be less than d + e

Mathematically;

f < d + e

f < 12 + 19

f < 31

So it could be 30

It could also range from 30 to 8

This is because if it is less than 8, then the addition to 12 will be less than or equal to 19

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2 PEERS PLUS ANOTHRR 2 PEER
ikadub [295]

Answer:

4.

Step-by-step explanation:

2+2 equals 4. Plus sign: + you add two on both sides, therefor you get 4 as your answer.

6 0
3 years ago
Read 2 more answers
Find the product of the roots of the equation<br> xl-5x - 36 = 0
Marat540 [252]

Answer:

Step-by-step explanation:

Hello, I assume that you mean

x^2-5x-36

The product is -36.

x_1 \text{ and } x_2 \text{ are the two roots, we can write}\\\\(x-x_1)(x-x_2)=x^2-(x_1+x_2)x+x_1\cdot x_2

So in this example, it means that the sum is 5 and the product is -36.

Thank you

5 0
3 years ago
Assume that the probability of a defective computer component is 0.02. Components arerandomly selected. Find the probability tha
solmaris [256]

Answer:

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

7th defective, with 0.02 probability. So

p = (0.98)^6*0.02 = 0.0177

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

Find the expected number and variance of the number of components tested before a defective component is found.

Inverse binomial distribution, with p = 0.02

Expected number before 1 defective(n = 1). So

E = \frac{n}{p} = \frac{1}{0.02} = 50

Variance is:

V = \frac{np}{(1-p)^2} = \frac{0.02}{(1-0.02)^2} = 0.0208

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

5 0
3 years ago
Use the Distributive Property to rewrite the expression. 9(y + 4)
Ulleksa [173]

Answer:

Answer would be 9y+36

Step-by-step explanation:

Because if you distribute the 9 inside the parenthesis, you'd get

9*y=9y and 9*4=36

so 9y+36

Hope my answer was helpful to you!

7 0
3 years ago
I need help, with these two answers..
8090 [49]

download answer here

5 0
3 years ago
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