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Andrew [12]
2 years ago
5

3 1/5 divided by 1 1/2

Mathematics
1 answer:
Novay_Z [31]2 years ago
8 0

Answer:

2.13333333333

Step-by-step explanation:

First you do 5x3+1 = 16/5

Second, you do 2x1+1 = 3/2

Third, you divided 16/5 by 3/2.

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Someone please help me on math please
Ratling [72]
The answer is 0.12 millimeters because if you multiplied the numbers it would give you 0.12 mm hope this is correct
5 0
2 years ago
-10 < 2x - 4 < 8, What is X?
Crank

Add 4 to the whole equation

-10 + 4 < 2x < 8 + 4

Simplify

-6 < 2x < 12

Divide the whole equation by 2

-6/2 < x < 12/2

Simplify

<u>-3 < x < 6</u>

5 0
3 years ago
Read 2 more answers
Neeeeeed heeelp plz!!!
Blababa [14]
                             |
                             |__x_- 4___________              2x³/2x² =x
   2x² + 2x +3        | 2x³ - 6x² +7x +3
                            - (<span>2x³ +2x² +3x)
</span>                                      -8x² +4x  +3                -8x²/2x² = -4
                                    <span>-(-8x² -8x  -12)
</span>                                              12x +15

(x-4) + (12x +15)/(2x² + 2x +3) 
6 0
3 years ago
Triangle DEF has vertices D(−4, 1), E(2, 3), and F(2, 1) and is dilated by a factor of 3 using the point (1, 1) as the point of
CaHeK987 [17]

Answer: D'(-14,1);\ E'(4,7);\ F'(4,1)

Step-by-step explanation:

Since the center of dilation is not at the origin, we can use the following formula in order to find the coordinates of the vertices of the triangle D'E'F':

D_{O,k}(x,y)=(k(x-a)+a, k(y-b)+b)

Where "O" is the center of dilation at (a,b) and "k" is the scale factor.

In this case you can identify that:

(a,b)=(1,1)\\k=3

Therefore, susbtituting values into the formula shown above, you get that the coordinates ot the resulting triangle D'E'F, are the following:

Vertex D' → (3(-4-1)+1,\ 3(1-1)+1)=(-14,1)

Vertex E' → (3(2-1)+1,\ 3(3-1)+1)=(4,7)

Vertex F' → (3(2-1)+1,\ 3(1-1)+1)=(4,1)

6 0
3 years ago
A total of 50,000 contestants are chosen for a survey. A
ankoles [38]
I am pretty sure it is linear decrease,
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