Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
B. 16.30 = 16.3
if there is a 0 in a decimal and it is the farthest right place value it is the same as if the 0 wasn't there
Answer:

Step-by-step explanation:
Step 1:-
using logarithmic formula 
so given 
now simplify
= 
<u>Answer:</u>-
![log(x^{3}y^{2})= [tex]3 log x+2 log y](https://tex.z-dn.net/?f=log%28x%5E%7B3%7Dy%5E%7B2%7D%29%3D%20%5Btex%5D3%20log%20x%2B2%20log%20y)
I believe that x=4 would be the answer
Answer:
You could have a square with side of 50 ft.
Step-by-step explanation: