6y + 40 = 100 What is y?

Mathematics

2 answers:

Fantom [35]3 years ago

8 0

$\begin{gathered}\\ \sf\longmapsto 6y+40=100\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 6y=100-40\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 6y=60\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto ⚘y=10\end{gathered}$

timofeeve [1]3 years ago

5 0

Answer:

y=10

Step-by-step explanation:

6y+40=100

Subtract 40 from both sides.

6y=100−40

Subtract 40 from 100 to get 60.

6y=60

Divide both sides by 6.

y=10

Hope this helped you! :)

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According to a recent publication, the mean price of new mobile homes is $63 comma 800. Assume a standard deviation of $7900.

wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,580, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,117, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}$

For n=25 we have:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580$

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117$