All categories

3 years ago

Choose the polynomial written in standard form.

Mathematics

2 answers:

Olin [163]3 years ago

8 0

Answer:

x4 + 4x3 + 10x

Step-by-step explanation:

Semenov [28]3 years ago

4 0

Answer:

$x^4 + 4x^3 + 10x$

Step-by-step explanation:

A polynomial written in decreasing order of the degree of its monomials ( or single term ) is called its standard form,

In polynomial,

$x^2 + 4x^4 + 10x^6$ ,

Degrees are written in increasing order,

⇒ It is not written in standard form,

In polynomial,

$x^4 + 4x^3 + 10x$ ,

Degrees are written in decreasing order,

⇒ It is written in standard form,

In polynomial,

$x^7 + 4x^3 + 10x^4$ ,

There is no order of degrees,

⇒ It is not written in standard form,

In polynomial,

$x^6 + 4x^3 + 10x^7$ ,

There is no order of degrees,

⇒ It is not written in standard form,

You might be interested in

The quotient of a number and 2 is -3 ?

Vera_Pavlovna [14]

The answer to this is x/2 = 3.

4 0

4 years ago

Read 2 more answers

Raul ate 7/8 of 1/2 a pizza. How much of the pizza did Raul eat?

3241004551 [841]

Answer:

7

Step-by-step explanation:

7/8× 1/2=

7 × 1

8 × 2

=7/16

5 0

3 years ago

What is 78,000,000 in scientific notation

fomenos

Answer:

7.8×10⁷

Step-by-step explanation:

You want to keep the coefficient (7.8) between 1 and 10 to achieve a normalized notation. Otherwise 78×10⁶ would also be an option.

3 0

3 years ago

Read 2 more answers

Help Please!! Ill Give Brainliest!

vladimir1956 [14]

Question:

On a coordinate grid, point A is located in the first quadrant. Point B is located at (negative 1 over 2, 2).

Point C is a reflection of point B across the y-axis. Which graph shows these three points?

Answer:

What are you telling me? I would help, but can you type in answer choices if there is. That would be very helpful. I don't understand what is " A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 4 grid lines to the right of the y-axis and 1 grid line above the axis. Point B is plotted at 1 grid line to the left of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the left of the y-axis and 4 grid lines below the x-axis.

A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 4 grid lines to the right of the y-axis and 1 grid line above the x-axis. Point B is plotted at 1 grid line to the left of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis.

A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 2 grid lines to the left of the y-axis and 4 grid lines above the axis. Point B is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the left of the y-axis and 4 grid lines below the x-axis.

A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 2 grid lines to the left of the y-axis and 4 grid lines above the axis. Point B is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the right of the y-axis and 4 grid lines below the x-axis."

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone please explain how to do this!!!

DedPeter [7]

Hi there!

So we are given that:-

tan theta = 7/24 and is on the third Quadrant.

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

Using the Identity

$\large \displaystyle{ {tan}^{2} \theta + 1 = {sec}^{2} \theta}$

Substitute tan theta = 7/24 in.

$\large \displaystyle{ {( \frac{7}{24}) }^{2} + 1 = {sec}^{2} \theta }$

Evaluate.

$\large \displaystyle{ \frac{49}{576} + 1 = {sec}^{2} \theta} \\ \large \displaystyle{ \frac{625}{576} = {sec}^{2} \theta}$

Reminder -:

$\large \displaystyle{ sec \theta = \frac{1}{cos \theta} }$

Hence,

$\large \displaystyle{ \frac{576}{625} = {cos}^{2} \theta} \\ \large \displaystyle{ \sqrt{ \frac{576}{625} } = cos \theta} \\ \large \displaystyle{ \frac{24}{25} = cos \theta}$

Because in QIII, cos<0. Hence,

$\large \displaystyle \boxed{ \blue{cos \theta = - \frac{24}{25} }}$

Using the Pythagorean Theorem

$\large \displaystyle{ {a}^{2} + {b}^{2} = {c}^{2} }$

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

$\large \displaystyle{ {7}^{2} + {24}^{2} = {c}^{2} } \\ \large \displaystyle{49 + 576 = {c}^{2} } \\ \large \displaystyle{625 = {c}^{2} } \\ \large \displaystyle{25 = c}$

Thus, the hypotenuse side is 25. Using the cosine ratio:-

$\large \displaystyle{cos \theta = \frac{adjacent}{hypotenuse}}$

Therefore:-

$\large \displaystyle{cos \theta = \frac{24}{25} }$

Because cos<0 in Q3.

$\large \displaystyle \boxed{ \red{cos \theta = - \frac{24}{25} }}$

Hence, the value of cos theta is -24/25.

Let me know if you have any questions!

8 0

3 years ago