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3 years ago

Indicate the equation of the line through (2, -4) and having slope of 3/5.

Mathematics

2 answers:

AlladinOne [14]3 years ago

8 0

oh sheet this is kinda hard but i know bc im best in the skreets ( 7) ,69

antiseptic1488 [7]3 years ago

4 0

<h3>Answer:</h3>

3x-5y=26

Step-by-step explanation:

Indicate the equation of the line through (2, -4) and having slope of 3/5.

<em>If you are doing this on Odyssey then click on each letter and number and drag it onto the grey area and drop it there .. you do not have to fill every grey square.</em>

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Hey guys<br>im new here<br>please solve this for me with steps!<br>ill mark as the best answer

Vinil7 [7]

Answer:

The factors of $2(x+y)^2-9(x+y)-5$ is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=> $2(x+y)^2-9(x+y)-5$

To Find:

The factors of the polynomial =?

Solution:

Lets assume k = (x+y)

Then $2(x+y)^2-9(x+y)-5$ can be written as $2k^2-9k-5$

Now by using quadratic formula

k = $\frac{-b\pm\sqrt{(b^2-4ac}}{2a}$

where

a= 2

b= -9

c= -5

Substituting the values, we get

k = $\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}$

k = $\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}$

k = $\frac{-(-9) \pm \sqrt{(81+40)}}{4}$

k = $\frac{-(-9) \pm \sqrt{(121)}}{4}$

k = $\frac{-(-9) \pm 11}}{4}$

k= $\frac{ 9 \pm 11}{4}$

k = $\frac{20}{4}$ k = $\frac{-2}{4}$

$k_1 =5$ $k_2 = -\frac{1}{2}$

$2k^2-9k-5= 2(k-5)(k+\frac{1}{2})$

Solving the RHS we get

$\frac{2}{2}(k-5)(2k+1)$

$(k-5)(2k+1)$

Substituting k = x+y

$((x+y)-5)(2(x+y+1)$

$((x+y)-5)(2x+2y+1)$

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Step-by-step explanation:

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The statement explains why the ordered pair is a solution to the system of equations. Is the statement true or false? True False

tigry1 [53]

The system of the equation doesn't give the solution at (-3, -6).

<h2>Given to us</h2>

-4x+y = 6
5x-y =21

<h3>Equation 1,</h3>

-4x+y = 6

solve for y

$-4x+y =6\\y= 6+4x$

<h3>Equation 2,</h3>

5x-y =21

substitute the value of y in equation 2,

$5x-(6+4x) =21\\5x -6 -4x =21\\5x -4x=21+6\\x = 27$

Substitute the value of x in equation 2,

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We can see that the solution of the two equations is at (27, 114). Also, it can be verified by plotting the line on the graph.

Hence, the system of the equation doesn't give the solution at (-3, -6).

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