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3 years ago

9. A quadratic function g(x) passes through the points (-8, 33), (2, 1), and (8, 1).

Mathematics

1 answer:

Semmy [17]3 years ago

3 0

Answer:

x(-8+y)-33+y(2+x)+1-x(8-y)+1

Step-by-step explanation:

this is a quadratic function g(x) passing through the points

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3 years ago

Divide (x3 - 2x² + 6x - 8) by (x - 2)<br> -<br> How can I (x3 - 2x² + 6x - 8) by (x - 2)

Blababa [14]

Answer:

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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3 years ago

Pre-calc, image attached

makvit [3.9K]

Answer:

$\lim_{x \to 7} \frac{\sqrt{x+2}-3 }{x-7} = \frac{1}{6}$

Step-by-step explanation:

$\lim_{x \to 7} \frac{\sqrt{x+2}-3 }{x-7}$

$\frac{\sqrt{x+2}-3 }{x-7}$

$\frac{\frac{1}{2} (x+2)^{-\frac{1}{2} }}{1}$ <-- Take derivative of numerator and denominator expressions

${\frac{1}{2} (x+2)^{-\frac{1}{2} }}$ <-- Simplify

$\frac{1}{2}(\frac{1}{\sqrt{x+2} })$ <-- Rewrite

$\frac{1}{2}(\frac{1}{\sqrt{7+2} })$ <-- Use direct substitution and plug in the limit x=7

$\frac{1}{2}(\frac{1}{\sqrt{9} })$

$\frac{1}{2}(\frac{1}3 })$

$\frac{1}{6}$

Therefore, $\lim_{x \to 7} \frac{\sqrt{x+2}-3 }{x-7} = \frac{1}{6}$

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3 years ago

Find the median of the data. 12,33,18,28,29,12,17,4,2

arsen [322]

Answer:

Step-by-step explanation:

2, 4, 12, 12, 17, 18, 28, 29, 33

(17+18)/2

35/2= 17.5 is the median

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2 years ago