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3 years ago

7

Please help on this. I am confused.

1 answer:

neonofarm [45]3 years ago

3 0

The answer is 2x^2-3x-2.

To solve this, you take f(x)-g(x) which is 2x^2-5-3x+3. This simplifies to 2x^2-3x-2.

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If f(x) = -5x - 1, find the function value f(1).<br><br> f(1) =

denis23 [38]

Answer: f(1) = -6

Please mark me as Brainliest

5 0

3 years ago

Candice drives a total of 48 miles each day to work and get back home. She works five days a week. Her car gets 21 miles per gal

slega [8]

Answer:

Total gallon of fuel used = $11.428$ gallons

Step-by-step explanation:

Given -

The total distance travelled by car in one gallon of gas = 21 miles

Total distance travelled each day = 48 miles

Number of days days in a week in which Candice drive is 5 days

Total miles travelled per week = $48*5$ = 240 miles

Total gallon of fuel used = $\frac{240}{21} = 11.428$ gallons

5 0

3 years ago

An altitude of a triangle is a line or segment that passes through a vertex of the triangle and is _____________ to the line con

GenaCL600 [577]

I think best word to insert in the blank is the term "bisecting".

An altitude of a triangle is a line or segment that passes through a vertex of the triangle and is bisecting <span>to the line containing the opposite side.

</span>"Bisect<span>" means to divide into two equal parts which is true for the altitude of a triangle.</span>

3 0

3 years ago

Read 2 more answers

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago

Someone help me with this one

frosja888 [35]

Answer:

2/3

Step-by-step explanation:

20% = 12

48

1/6 = 8

left = 40

40/60 = 4/6

4/6 = 2/3

3 0

4 years ago

Read 2 more answers