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3 years ago

Please help on this. I am confused.

Mathematics

1 answer:

neonofarm [45]3 years ago

3 0

The answer is 2x^2-3x-2.

To solve this, you take f(x)-g(x) which is 2x^2-5-3x+3. This simplifies to 2x^2-3x-2.

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pishuonlain [190]

Answer:

GCHE

Step-by-step explanation:

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2 years ago

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Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av

Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving to the airport (in mph)

⇒ v + 15 = average speed driving from the airport (in mph)

Using: distance = speed x time

$\implies t=\dfrac{d}{v}$

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

$\implies t=\dfrac{18}{v} \ \ \textsf{and} \ \ t=\dfrac{18}{v+15}$

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

$\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1$

Now all we have to do is solve the equation for v:

$\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1$

$\implies \dfrac{18(v+15)+18v}{v(v+15)}=1$

$\implies 18(v+15)+18v=v(v+15)$

$\implies 18v+270+18v=v^2+15v$

$\implies v^2-21v-270=0$

$\implies (v-30)(v+9)=0$

$\implies v=30, v=-9$

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0

2 years ago

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Help me, please I need this

Alex17521 [72]

Answer:

B) y = -3x - 5

Hope this helps!

Please be kind to mark Brainliest.☺

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3 years ago

Evaluate the expression when x=3 and y=-6 7y-x

Alenkasestr [34]

7(-6) - 3
-42 -3
-45
Your answer is -45

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3 years ago

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Algebra 2 (8x2-7)+(8-8x2)

Katarina [22]

The answer is just 1 l, just didn’t on the top of my head.

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3 years ago

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