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Anastaziya [24]
4 years ago
14

Li and Jen went shopping. • Li bought 5 pairs of earrings and 1 necklace for a total of $63. • Jen bought 1 pair of earrings and

2 necklaces for a total of $36. Each pair of earrings cost e dollars and each necklace cost n dollars. Which system of equations can be used to find the cost, in dollars, of each pair of earrings and each necklace?
Mathematics
1 answer:
irina1246 [14]4 years ago
5 0

Answer:

<h2>Earing is $13</h2><h2>Necklace is $10</h2>

Step-by-step explanation:

Firstly, let us express the cost

for Li

5e+n=63---------1

for Jen

e+2n=36---------2

the system of equations are

5e+n=63----1

e+2n=36-----2

Multiply 1 by 1 and 2 by 5 to eliminate e we have

 5e+n=63

 5e+10n=180

-0-9n=-117

9n=117

Divide both sides by 9 we have

n=117/9

n=13

put n=13 in eqn 1 we have

e+2(13)=36

e+26=36

e=36-26

e=10

Earing is $13

Necklace is $10

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You get GPS units from two manufacturers, A and B. You get 43% of your units from A and 57% of your units from B. In the past, 2
defon

Answer:

0.5015 = 50.15% probability that it came from manufacturer A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: From manufacturer A.

Probability a unit is defective:

2% of 43%(from manufacturer A)

1.5% of 57%(from manufacturer B). So

P(A) = 0.02*0.43 + 0.015*0.57 = 0.01715

Probability a unit is defective and from manufacturer A:

2% of 43%. So

P(A \cap B) = 0.02*0.43 = 0.0086

What is the probability that it came from manufacturer A?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0086}{0.01715} = 0.5015

0.5015 = 50.15% probability that it came from manufacturer A.

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3 years ago
Consider the equation, where p is a real number coefficient.
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3 years ago
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. We learned about the de
attashe74 [19]

The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: \frac{x}{12\pi } = \frac{130}{360}

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

Step-by-step explanation:

a) \frac{arclength}{2\pi.r } = \frac{mAB}{360}, where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = \frac{mAB.2.\pi.r }{360}

arc length = \frac{90.2.3.14.6}{360}

arc length = 9.4

The arc lenght for the image is 9.4 inches.

b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):

\frac{x}{2.6.\pi } = \frac{130}{360}

\frac{x}{12\pi } = \frac{130}{360}

c) Resolving (b):

x = \frac{130.12.3.14}{360}

x = 13.6

The arc length for the image is 13.6 inches.

6 0
4 years ago
A jar is filled with only dimes and quarters. The jar contains a total of 60 coins and the value of the jar is $11.25. How many
inessss [21]

Answer:

35 quarters

Step-by-step explanation:

This situation has two unknowns - the total number of dimes and the total number of quarters. Because we have two unknowns, we will write a system of equations with two equations using the two unknowns.

  • d+q=60 is an equation representing the total number of coins
  • 0.10d+0.25q=11.25 is an equation representing the total value in money based on the number of coin. 0.10 and 0.25 come from the value of a dime and quarter individually.

We write the first equation in terms of q by subtracting it across the equal sign to get d=60-q. We now substitute this for d in the second equation.

0.10(60-q)+0.25q=11.25\\6-0.10q+0.25q=11.25\\6+0.15q=11.25

After simplifying, we subtract 6 across and divide by the coefficient of q.

6+0.15q=11.25\\0.15q=5.25\\q=35

We now know of the 60 coins that 35 are quarters. To find the total value of the quarters, we multiply 35 by 0.25 and find 8.75.

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