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Tpy6a [65]
3 years ago
14

A small organic food store makes two types of fruit smoothies: tropical and sport. Each tropical smoothie uses 9 oz of orange ju

ice and 6 oz of milk. Each sport smoothie uses 3 oz of orange juice and 3 oz of milk. The store stores the orange juice in a 210-oz container and milk in an 150-oz container. The store sells the tropical smoothies for $4 and sells the sport smoothie for $3. What is the maximum in sales the store can make from 1 container each of orange juice and milk?
$100

$110

$150

$280
Mathematics
2 answers:
Brilliant_brown [7]3 years ago
6 0

$150 is your answer........................................................


AlexFokin [52]3 years ago
3 0

Amount of orange juice that given container can hold = 210 -oz

Amount of milk that given container can hold = 150 -oz

1 tropical smoothie = 9 oz of orange juice + 6 oz of milk.

1 sport smoothie = 3 oz of orange juice + 3 oz of milk.

Number of packets of orange juice collected from 210 -oz for tropical smoothie if 9 -oz of orange juice is required = \frac{210}{9}=\frac{70}{3}= 23 packets (approx)

Number of packets of milk collected from 150 -oz for tropical smoothie if 6 oz of milk is required

 = \frac{150}{6}=\frac{50}{3} = 16 packets

Maximum number of Tropical smoothie= 16

Number of packets of orange juice collected from 210 -oz for sport smoothie  if 3-oz of orange juice is required =\frac{210}{3} =70 packets

Number of packets of milk collected from 210 -oz for sport smoothie  if 3 oz of milk is required =\frac{150}{3}= 50 packets

Maximum number of sport smoothie = 50

Total cost of 16 tropical smoothie , if the cost of one tropical smoothie is $ 4 = 16 × 4= $ 64

Total cost of 50 milk smoothie , if the cost of one sport smoothie is $ 3 = 50 × 3 = $ 150

The maximum  in sales the store can make from 1 container each of orange juice and milk is Sport smoothie , the total number being 50, having cost $ 150.→→→Option (C)

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