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Novosadov [1.4K]
3 years ago
15

5. Solve using inverse operations. 8 - 8=7 Pleasesssvhelp

Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0

Answer:

5

Step-by-step explanation:

r3

lara31 [8.8K]3 years ago
7 0

Answer:

15 -5+8=

=18

Step-by-step explanation:

you have add the 8 and 7 and then - 5 and then you add 8 more

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OLga [1]
B cuz x is five and 6.5 is 30
5 0
3 years ago
On August 2nd, 1988, a US District Court judge imposed a fine on the city of Yonkers, New York, for defying a federal court orde
Minchanka [31]

Answer:

a)

A(t) = 1,000,000 + 10,000,000t

B(t)= 0.01 +0.02t

b) No.

Step-by-step explanation:

a)<u> Penalty A:</u> 1 million dollars on August 2 and the fine increases by 10 million dollars each day thereafter.

If t represents the number of days after August 2,

A(t) = 1,000,000 + 10,000,000t

<u>Penalty B</u>: 1 cent on August 2 and the fine doubles each day thereafter.

A(t) = 0.01 + 2t(0.01) = 0.01 + 0.02t

b) Assuming your formulas in part (a) hold for t≥0, is there a time such that the fines incurred under both penalties are equal?

To solve this, we would have to equal both formulas and solve for t.

1,000,000 + 10,000,000t=0.01+0.02t\\9,999,999.98t=-999,999.99

By taking a look at this equation, we see that when we solve for t, t will be a negative number. Since the formulas are valid for t≥0, we can conclude that there won't be a time such that the fines are equal.

4 0
3 years ago
How to solve this math problem
Bumek [7]

Answer:

5.833

Step-by-step explanation:

3 0
3 years ago
The data shown are hourly wages of some employees of a small company. $5, $7, $8, $10, $24, $40 Which values, if any, are outlie
igor_vitrenko [27]
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3 0
4 years ago
If s and t are integers greater than 1 and each is a factor of the integer n, which of the following must be a factor of n st ?
yulyashka [42]

Answer:

A) None

Step-by-step explanation:

1) s^t shoudnt neccesarily be a factor of nst, for example, if s = 3, t = 4, and n = 12, then both s and t are factors of n, but 3^4 = 81 is not a factor of nst = 144.

2) (st)^2 shoudnt neccesarily be a factor of nst. Let s be 4, let t be 6, and let n be 12. Then n is a factor of both s and t, but (st)^2 = 24^2 is not a factor of nst = 12*24. In fact, it is a greater number.

3) Again, s+t isnt necessarily a factor of nst, let s be 2 and t be 3. Then both s and t are factor of n = 12. However 5 = s+t is not a factor of nst = 72.

So, neither of the three options is guaranteed to be a factor of nst. In fact, for s = 4, t = 6, and n = 12, none of the three options are valid.

4 0
3 years ago
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