For every 24meals Momoka prepared for customers last night, she prepared 2 meals for employees. Momoka prepared 156 meals.
2 answers:
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Answer:
Step-by-step explanation:
Let X be the length of pregnancy.
X is N(268, 15)
a) Prob of pregnancy lasting 307 days or longer
= P(X>307) =
=0.5-0.4953
=0.0047
b) Lowest 2% is 2nd percentile
Z=-2.55
X score = 268-2.55(15)
= 229.75 days
If length of days >230 days then it is not premature.
Answer:
The sample size is
Step-by-step explanation:
From the question we are told that
The margin of error is E =4.266
The standard deviation is
From the question we are told the confidence level is 99% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of is
Generally the sample size is mathematically represented as
=>
=>