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klasskru [66]
3 years ago
8

Find the area of square of one of its side is (3x+4y)cm.If x=4 and y=1,find its actual area.​

Mathematics
1 answer:
kumpel [21]3 years ago
7 0

Answer:

Step-by-step explanation:

hello :

the area is : (3x+4y)²cm²    when :x=4 and y=1, the area is : (3(4)+4(1))²cm² =16²cm2=256cm²

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PLEASE HELP ME WITH THESE FOUR QUESTIONS TYSMMM!!! THANK YOU
Dima020 [189]

Answer:

107^\circ, 133^\circ, 20^\circ, \text{and}, 23^\circ

Step-by-step explanation:

9. For the lines 'm' and 'n' to be parallel the sum of interior angles should be 180 degrees that is:

x+73^\circ=180^\circ

x=107^\circ

10. For the lines  'm' and 'n' to be parallel the alternate exterior angles should be equal that is:

147^\circ=x+14^\circ

x=147^\circ-14^\circ

x=133^\circ

11. For the lines  'm' and 'n' to be parallel alternate angles should be equal that is:

180^\circ-3x=2x+20^\circ

Solving for 'x' we get:

180^\circ-20^\circ=3x+2x

5x=160^\circ

x=32^\circ

12. For the lines  'm' and 'n' to be parallel corresponding angles should be equal that is:

(7x-11)^\circ=(4x+58)^\circ

7x-4x=58^\circ+11^\circ

3x=69^\circ

x=\frac{69}{3}=23^\circ

8 0
3 years ago
In the expression 3x + 7, what is the coefficient?
san4es73 [151]

Answer:

3

Step-by-step explanation:

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3 years ago
PLEASE HELP!!!!!!! this is really hard!!!
bekas [8.4K]
When Anne Betty and Cynthia compared the amount of money each had, they discovered that Anne and Betty together had $12 Betty and Cynthia together had $18 and Anne and Cynthia together had $10. 
<span>Who had the least amount of money? and how much was it?
a +b = 12
b + c = 18
a + c = 10
So what I did is simple XD A logical guess and check. I started with a = 1, but that was to little. And also didn't match up. So I kept going up and got a = 2, b = 10, and c = 8</span>
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peter picked 35 buckets of strawberries the average number of strawberries in each of these buckets were 97 from the buckets the
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5 0
3 years ago
HELP A FELLA OUT WILL MARK BRAINLIEST
Brums [2.3K]

Answer:

y = 4sin [(1/2)t - (4/3)π ]  - 2

Step-by-step explanation:

For this question, do not be intimidated by the terminology, just realize the following:

for y = a sin [ (2π/T) t ]

a = amplitude = given as 4

T = period = given as 4π

phase shift is simply horizontal shift, positive values means the graph moves by that amount to left and negative values means the graph moves to the right.

vertical shift ... is well a shift vertically. positive values move the graph up vertically and negative values move the graph down vertically.

so... if we start with the basic formula:

y = a sin [ (2π/T) t ]

given a = 4 and T = 4π (substitute these values into the formula)

y = (4) sin [ (2π/4π) t ] = (4) sin [ (1/2) t ]

y = 4sin [(1/2)t ]

Now for the shifts:

given phase shift, aka horizontal shift is -(4/3)π, equation becomes

y = 4sin [(1/2)t - (4/3)π ]

given vertical shift is -2, the equation simply becomes

y = 4sin [(1/2)t - (4/3)π ]  - 2

3 0
4 years ago
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