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katrin2010 [14]
3 years ago
10

Is the following conditional true? If cs 2, then c < 4. yes no

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

Yes, C is lower than 4.

Explanation: If we think of

C as 2 and

S as 2

then we can apply multiplication (cs=c multiplied by s) and get 4. So, S and C cannot be any bigger than 2.

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Zia is building a plastic model rocket that has the combined shape of a cone and a cylinder as shown. additionally, the cylinder
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Answer:

226 cm^3

The mass of plastic used to make cylinder is greater

Step-by-step explanation:

Given:-

- The density of cone material, ρc = 1.4 g / cm^3

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Solution:-

- To determine the volume of plastic that remains in the cylinder after gouging out a hemispherical amount of material.

- We will first consider a solid cylinder with length ( L = 10 cm ) and diameter ( d = 6 cm ). The volume of a cylinder is expressed as follows:

                                  V_L =\pi  \frac{d^2}{4} * L

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                                 V_L = \pi \frac{(6)^2}{4} * 10\\\\V_L = 90\pi  cm^3\\

- Where the volume of hemisphere with diameter ( d = 6 cm ) is given by:

                                 V_h = \frac{\pi }{12}*d^3

- Determine the volume of hemisphere gouged out as follows:

                                 V_h = \frac{\pi }{12}*6^3\\\\V_h = 18\pi cm^3

- Apply the principle of super-position and subtract the volume of hemisphere from the cylinder as follows to the nearest ( cm^3 ):

                               V = V_L - V_h\\\\V = 90\pi - 18\pi \\\\V = 226 cm^3

Answer: The amount of volume that remains in the cylinder is 226 cm^3

- The volume of cone with base diameter ( d = 6 cm ) and height ( h = 5 cm ) is expressed as follows:

   

                               V_c = \frac{\pi }{12} *d^2 * h

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                              V_c = \frac{\pi }{12} *6^2 * 5\\\\V_c = 15\pi cm^3

- The mass of plastic for the cylinder and the cone can be evaluated using their respective densities and volumes as follows:

                             m_i = p_i * V_i

- The mass of plastic used to make the cylinder ( after removing hemispherical amount ) is:

                           m_L = p_L * V\\\\m_L = 0.8 * 226\\\\m_L = 180.8 g

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                           m_c = p_c * V_c\\\\m_c = 1.4 * 15\pi \\\\m_c = 65.973 g

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