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diamong [38]
2 years ago
13

A red balloon is 40 feet above the ground and rising at 2 feet per second. At the same time, a blue balloon is 60 feet above the

ground and falling at a rate of 3 feet per second. How long will it take for the two balloons to be the same height from the ground? Let s = the number of seconds since the balloons began moving.
WRITE AN EQUATION FOR THIS.
Mathematics
1 answer:
VikaD [51]2 years ago
4 0

Answer:

40+2s=60-3s

Step-by-step explanation:

The red balloon starts 40 feet off the ground and rises 2 feet per second. This means the height of the red ballon is 40+2s.

The blue balloon starts 60 feet off the ground at starts falling 3 feet per second. This means the height of the blue balloon is 60-3s.

Because we want to find out when the balloons will be the same height, we set them equal to each other.

40+2s=60-3s

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Steps:

Radius= 17in

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Formula: V=πr2h

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Solved for volume

H= Height

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Description:

We know that R is 17 inches, and H is 10 inches. Since we are finding the volume we use the formula V=πr2h to calculate. After calculating your answer will come as V≈9079.2in³. You also said to round your answer to the nearest hundredth. After rounding your answer to th enearest hundredth your answer will come as 9,079.20.

Answer: V≈9079.2in³

Round to the nearest hundredth = 9,079.20

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<em><u>Hope this helps.</u></em>

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