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diamong [38]
3 years ago
13

A red balloon is 40 feet above the ground and rising at 2 feet per second. At the same time, a blue balloon is 60 feet above the

ground and falling at a rate of 3 feet per second. How long will it take for the two balloons to be the same height from the ground? Let s = the number of seconds since the balloons began moving.
WRITE AN EQUATION FOR THIS.
Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

40+2s=60-3s

Step-by-step explanation:

The red balloon starts 40 feet off the ground and rises 2 feet per second. This means the height of the red ballon is 40+2s.

The blue balloon starts 60 feet off the ground at starts falling 3 feet per second. This means the height of the blue balloon is 60-3s.

Because we want to find out when the balloons will be the same height, we set them equal to each other.

40+2s=60-3s

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Nathan can paint 2/9 of the fence in one day select all statements that correctly describes the process of finding how long it w
storchak [24]
Two and two-thirds of a day, but you should say three days.
8 0
3 years ago
Find the measure of angle2<br><br> A. 90<br> B. 50<br> C. 60<br> D. 30
galina1969 [7]
I think it is C. 60.
You can eliminate A because it is not a right angle, and D because the angle is bigger than the given angle. So it is between 50 and 60, and I hope this is right and the picture makes sense

6 0
3 years ago
Mr. James has cylindrical beakers that measure 4 inches in diameter and 9 inches high. What is the volume contained within the b
goblinko [34]
So 4 inches diameter result the radius is 4/2 = 2 inches 

area of base = pir^2 = 3,14*2^2 = 3,14*4 = 12,56 inches squared 

volume = area of base *height 

V = 12,56 *9 = 113,04 so rounded 113,05 inches cubed 

hope this will help you 
3 0
3 years ago
a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
4 years ago
Consider the continuous random variable x, which has a uniform distribution over the interval from 110 to 150. The probability t
Virty [35]

Answer:

The probability that x will take on a value between 120 and 125 is 0.14145

Step-by-step explanation:

For uniform distribution between a & b

Mean, xbar = (a + b)/2

Standard deviation, σ = √((b-a)²/12)

For 110 and 150,

Mean, xbar = (150 + 110)/2 = 130

Standard deviation, σ = √((150-110)²/12 = 11.55

To find the probability that x will take on a value between 120 and 125

We need to standardize 120 & 125

z = (x - xbar)/σ = (120 - 130)/11.55 = - 0.87

z = (x - xbar)/σ = (125 - 130)/11.55 = - 0.43

P(120 < x < 125) = P(-0.87 < x < -0.43)

We'll use data from the normal probability table for these probabilities

P(120 < x < 125) = P(-0.87 < x < -0.43) = P(z ≤ -0.43) - P(z ≤ -0.86) = 0.33360 - 0.19215 = 0.14145

Hope this Helps!!!

3 0
3 years ago
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