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diamong [38]
3 years ago
13

A red balloon is 40 feet above the ground and rising at 2 feet per second. At the same time, a blue balloon is 60 feet above the

ground and falling at a rate of 3 feet per second. How long will it take for the two balloons to be the same height from the ground? Let s = the number of seconds since the balloons began moving.
WRITE AN EQUATION FOR THIS.
Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

40+2s=60-3s

Step-by-step explanation:

The red balloon starts 40 feet off the ground and rises 2 feet per second. This means the height of the red ballon is 40+2s.

The blue balloon starts 60 feet off the ground at starts falling 3 feet per second. This means the height of the blue balloon is 60-3s.

Because we want to find out when the balloons will be the same height, we set them equal to each other.

40+2s=60-3s

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Write (8a^-3)^-4/3 in simplest form. <br><br> Please show your work!
german

Answer:

(a/2) ^4  or a^4/16

Step-by-step explanation:

(8a^-3)^-4/3

split into two parts

8^ -4/3   *  (a^-3)^-4/3

using the power to the power rule we can multiply the exponents

8^(-4/3)  *a^(-3*-4/3)

8^ (-4/3) * a^(4)

replace 8 with 2^3

(2^3)^(-4/3) * a^(4)

using the power to the power rule we can multiply the exponents

2^(3*-4/3) * a^(4)

2 ^ (-4) * a^4

the negative exponent means it goes in the denominator if it is in the numerator

a^4/2^4

make a fraction

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or a^2/16

8 0
3 years ago
Read 2 more answers
The time between a lightning flash and the following thunderclap may be used to estimate, in kilometers,
Natalija [7]
The answer is 3km as there is 9 secs between it and distance = time/3 and 9/3 =3 so distance =3
8 0
3 years ago
A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi
rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a  statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

P(9

Recall Chebyshev's inequality that

P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\

Comparing with the Ii equation which is appropriate here we find that

\mu =14.5

Next what we find is

k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071

Thus from the given information we find that

\mu = 14.5\\\sigma = 5.071\\k = 1.084

5 0
3 years ago
What is the measure of angle CED?
MA_775_DIABLO [31]

Answer:

h

Step-by-step explanation:

3 0
3 years ago
18=k+12 HELPPP WHATS K
Nana76 [90]

Answer:

k=6

Step-by-step explanation:

18=k+12

you need to isolate k so you subtract 12 from both side

6=k

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3 years ago
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