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Ivahew [28]
4 years ago
12

How would you solve for side a? Pythagorean theorem, cause if that's the case wouldn't

Mathematics
1 answer:
Yuri [45]4 years ago
3 0
The angle is 127°, so the Pythagorean theorem does not apply.

Generally, you would use the Law of Cosines to solve for the third side when given two sides and the angle between them.

EF^2 = 7^2 +15^2 -2*7*15*cos(127°)
EF ≈ √(400.3812) ≈ 20.00953

My guess is that you're expected to use 20 for the length of the 3rd side.

By Heron's formula, s = (7 +15 +20)/2 = 21

Area = √(21*(21 -7)*(21 -15)*(21 -20)) = √(21*14*6*1) = √1764 = 42 . . . . yd^2

_____
More directly,
.. Area = (1/2)*7*15*sin(127°) ≈ 41.928 . . . . yd^2

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Alex
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6 0
3 years ago
A box has a volume of 192 cubic inches, a length that is twice as long as its width, and a height that is 2 inches greater than
Volgvan

Answer:

Length = 8 inches

Width = 4 inches

Height = 6 inches

Step-by-step explanation:

Volume of the box = 192 cubic inches

Volume of a box = length × width × height

Let

Width = x

Length = 2x

Height = x + 2

Volume of a box = length × width × height

192 = 2x * x * (x + 2)

192 = 2x^2 (x + 2)

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Divide through by 2

96 = x^3 + 2x^2

Subtract 96 from both sides

x ^3 + 2x^2 - 96 = 0

Factorise

(x - 4) (x^2 + 6x + 24) = 0

x^2 + 6x + 24 has no real x-value

So,

Divide both sides by (x^2 + 6x + 24).

0 ÷ (x^2 + 6x + 24) = 0

So,

(x - 4) = 0

x = 4

Width = x = 4 inches

Length = 2x

= 2(4)

= 8 inches

Height = x + 2

= 4 + 2

= 6 inches

Check:

Volume of a box = length × width × height

= (8 * 4 * 6) inches

= 192 inches

4 0
4 years ago
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Answer:

A. Angles 1 and 4

D. Angles 2 and 3

Step-by-step explanation:

Alternate interior angles are a pair of angles which alternate each other lying on either side of the transversal but within the two parallel lines that is cut across by the transversal.

In the diagram above, the following are alternate interior angles:

<1 and <4,

<2 and <3

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Answer:

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Step-by-step explanation:

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