We want to recast the equation into the standard form equation for a circle centered at (h, k) with radius r. That equation is
... (x -h)² + (y -k)² = r²
Start by completing the square for both x-terms and y-terms.
... x² - 4x + y² + 4y = k
To do that, add the squares of half the coefficients of the x- and y-terms.
... x² - 4x + (-2)² + y² + 4y + 2² = k + (-2)² + 2²
... (x -2)² + (y +2)² = k + 8 = r² . . . . . this is now equal to the square of the radius, so we have
... k + 8 = 6² = 36
Subtracting 8 gives
... k = 28 . . . . . . . matches selection D)

looking at the picture above... you do have the radius, is just in the truncated part of the picture... so you have "h" and "r", so just plug them in
Lets find 32% of 500.
32/100 = .32
.32 * 500 = 160
Answer: 160 apples are rotten.
Answer:
the answer is x=15
Step-by-step explanation:
75/5=15
120/8=15
180/12=15
Hope this helps some.
Answer:
I'm not SUPER sure but, it only can exist where there is a region in a planetary system where liquid water might exist on the surface of a planet. That puts it in the "habitable zone" which is where it can exist.