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weqwewe [10]
3 years ago
11

Explain how the periodic table is arranged and why it is a helpful tool in our study of chemistry. Write in complete sentences a

nd use at least 4 sentences to complete your paragraph.
Please do not answer this unless you have a complete answer. I don't want point hoggers, I want people who know what they are talking about.
Chemistry
1 answer:
frosja888 [35]3 years ago
3 0
The periodic table is grouped by the properties of each element. They are also arranged in the order of their atomic mass.  Different rows of elements are called periods. If elements lie in the same column, they are in the same group. It is helpful to us today because it helps us gain new information on the properties and the world around us. We would not have a true understanding of Chemistry if it were not for the period table.

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Use the periodic table to predict which element has the LEAST metallic character--- silicon sodium krypton or potassium ??????
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Ka/KbMIXED PRACTICE108.Calculate the [H3O+(aq)], the pH, and the % reaction for a 0.50 mol/L HCN solution. ([H3O+(aq)] = 1.8 x 1
NeTakaya

Answer:

a) [H₃O⁺] = 1.8x10⁻⁵ M

b) pH = 4.75

c) % rxn = 3.5x10⁻³ %

Explanation:

a) The dissociation reaction of HCN is:

HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)

0.5 M - x                       x               x

The dissociation constant from the above reactions is given by:

Ka = \frac{[H_{3}O^{+}][CN^{-}]}{[HCN]} = 6.17 \cdot 10^{-10}

6.17 \cdot 10^{-10} = \frac{x*x}{(0.5 - x)}

6.17 \cdot 10^{-10}*(0.5 - x) - x^{2} = 0

By solving the above quadratic equation we have:

x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]

Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.

b) The pH is equal to:

pH = -log[H_{3}O^{+}] = -log(1.75 \cdot 10^{-5} M) = 4.75    

Then, the pH of the HCN solution is 4.75.

c) The % reaction is the % ionization:

\% = \frac{x}{[HCN]} \times 100

\% = \frac{1.75 \cdot 10^{-5} M}{0.5 M} \times 100

\% = 3.5 \cdot 10^{-3} \%          

Therefore, the % reaction or % ionization is 3.5x10⁻³ %.

I hope it helps you!      

6 0
3 years ago
There are two alloys, one is 1 part silver and 5 parts copper and the other 3 parts silver and 1 part copper are mixed to form 3
borishaifa [10]
Lets make x equal the number times you use the 1/5 ratio alloy and y equal the number of times you use the 3/1 ratio alloy.  You can make the equation (x+3y)-(5x+y)=0 and (x+3y)+(5x+y)=350
Then you can make the system of equation of:
-4x+2y=0 (this is y=2x)
 6x+4y=350  
You can make 6x+8x=350 by through substitution and solve of x.
14x=350
x=25 (which means y=50)

that means that the weight of the 1/5 ratio alloy is 150 pounds.
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the weight of the 3/1 ratio alloy is 200 pounds.
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I hope this helps.

3 0
3 years ago
Question 19 Write a balanced half-reaction for the oxidation of gaseous nitrogen dioxide to nitrate ion in acidic aqueous soluti
Alexxx [7]

Answer:

This will be the balanced half reaction:

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Explanation:

In acidic medium, the redox balance has to be done as this way.

As it is an oxidation, we know that oxidation state has increased.

NO₂(g)   →  NO₃⁻(aq)  + 1 e⁻

Nitrogen in NO₂ acts with +4; in the nitrate, N acts with +5

The nitrogen has released 1 electron.

As we are in acidic medium, we must complete with water, in the same side, as we have less oxygens and in the opposite side, with protons to balance the H. This will be the balanced half reaction:

NO₂(g)  + H₂O (l) →  NO₃⁻(aq)  + 1 e⁻  + 2H⁺ (aq)

5 0
3 years ago
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