11.27 mol of carbon dioxide gas is equal to 252.45 L or 270.48 L
<h3>Further explanation</h3>
Given
11.27 mol of CO2
Required
Volume of gas
Solution
If the conditions are assumed to be at the STP state (Standard Temperature and Pressure) at T 0 ° C and P 1 atm, then Vm is 22.4 liters/mol.
so for 11.27 moles the total volume is:
11.27 mol x 22.4 L = 252.45 L
But if the conditions are assumed to be at RTP (Room Temperature and Pressure), Conditions at T 25 ° C and P 1 atm. Vm = 24 liters/mol, then the volume of CO2:
11.27 mol x 24 L = 270.48 L.
52.0 divided by 65 g/mol gives you 0.8mol
Absorbance values greater than or equal to 1.0 are too high. If you are getting absorbance values of 1.0 or above, your solution is too concentrated. Simply dilute your sample and recollect data . Keep in mind that absorbance is the logarithm of the transmission (T) of light through a sample
Hope this help
Facilitated diffusion is your answer
The poly atomic ion formula for ammonium would be NH4+