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liraira [26]
3 years ago
9

Which atom has a change of oxidation number of +4 in the pictured redox reaction?

Chemistry
1 answer:
SpyIntel [72]3 years ago
3 0

Answer:

The answer to your question is the letter d. S

Explanation:

Data

Change of +4 in the oxidation number

Chemical reaction

               K₂Cr₂O₇  +  H₂O  +  S  ⇒   KOH  +  Cr₂O₃  +  SO₂    

Process

1.- Calculate the oxidation numbers following the rules.

Some rules

  H = +1       O = -2    Alkali metals = + 1    Alkali earth metals = +2    

K₂⁺¹Cr₂⁺⁶O₇⁻²  +  H₂⁺¹O⁻²  +  S⁰  ⇒   K⁺¹O⁻²H⁺¹  +  Cr₂⁺³O₃⁻²  +  S⁺⁴O₂⁻²    

Elements that changed their oxidation numbers

                       Cr₂⁺⁶   ---------------- Cr₂⁺³

                       S⁰       --------------- S⁺⁴

                     

 

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What is the mass in kilograms of an object that weighs 50.0lbs?
Aleonysh [2.5K]

The amount of matter in an object is said to be its mass. The SI base unit of mass is kilograms i.e. kg.

The mass of the object = 50.0 lbs (given)

For converting lbs to kg:

1 lb = 0.453592 kg

So, 50 lbs = 50\times 0.453592 kg = 22.6796 kg \simeq 22.68 kg

Hence, the mass of 50.0lbs object in kilograms is 22.68 kg.

5 0
3 years ago
4.14 Oxygen requirement for growth on glycerol Klebsiella aerogenes is produced from glycerol in aerobic culture with ammonia as
Iteru [2.4K]

Answer:

0.37 g

Explanation:

The molecular weight for Glycerol = 92

Number of Carbon atoms in glycerol (x)  C_3H_8O_3 = 3

Molecular weight of  the Biomass  ( Klebsiella aerogenes )

= CH_{1.73}O_{0.43}N_{0.24}

= \frac{23.97}{0.92}

= 26.1

From the molecular weight of the Biomass, we can deduce the Degree of reduction for the substrate(glycerol denoted as \delta _g) as follows:

= (4×1)+(1×1.73)-(2×0.43)-(3×0.24)

= 4.15

Given that the yield of the Biomass = 0.40 g

However;

C = Yield of Biomass *\frac{Molecular weight of substrate}{Molecular weight of the Biomass}

C = 0.40*\frac{92}{26.1}

C = 1.41 g

Now , the oxygen requirement can be calculated as:

= \frac{1}{4}*(n*S -  C * \delta _{g})

= \frac{1}{4}(3*4.7-1.41*4.15)

= 2.1 g/mol

Hence, we can say that the needed oxygen = 2.1 g/mol of the substrate consumed.

Now converting it to mass terms; we have:

= 2.1*\frac{number of mole of oxygen}{molecular weight of glycerol}

= 2.1 * \frac{16}{92}

= 0.3652 g

≅ 0.37 g

∴ The oxygen requirement for this culture in mass terms = 0.37 g

3 0
3 years ago
There are 15 technicians and 11 chemists working in a research laboratory. In how many ways could they form a 5-member safety co
Fynjy0 [20]

a)

26C5 -> 26 choices of 5 things

b)

15C1 × 11C4

c)

11C1 × 15C4

d)

11C2 × 15C2

e)

11C4

or

15C4

5 0
3 years ago
If your experimentally measured volume of the bolt was too small, would that make the density value larger or smaller?
MakcuM [25]
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4 0
3 years ago
A canister of neon contains 4.8x1024 atoms of the gas. How many moles of neon are present in the canister?
algol [13]

Answer:

7.97 moles of neon are present in the canister.

Explanation:

Avogadro's constant or "Avogadro's number" is the number of constituent particles found in the amount of substance in one mole.

In other words, Avogadro's number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

So, you can apply the following rule of three: if 6.023*10²³ atoms are present in 1 mole, 4.8*10²⁴ atoms are present in how many moles?

amount of moles=\frac{4.8*10^{24}atoms*1 mole }{6.023*10^{23}atoms}

amount of moles= 7.97 moles

<u><em>7.97 moles of neon are present in the canister.</em></u>

4 0
3 years ago
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