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adoni [48]
2 years ago
10

Simplifica fractia 2n+6n supra 2​

Mathematics
1 answer:
nignag [31]2 years ago
5 0

Answer:

Step-by-step explanation:

1234

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Mark is going to an awards dinner and wants to dress appropriately. He has one blue dress shirt, one white dress shirt, one blac
dlinn [17]

Solution:

Outfit         Shirt       Slacks        Tie

Outfit 1      Blue        Black         Red

Outfit 2     Blue        Grey          Red

Outfit 3    White       Black         Red

Outfit 4    White       Grey          Red

Outfit 5    Black       Black         Red

Outfit 6    Black       Grey         Red

We take the outfits 1, 2 , 5  and 6 as a subset of the sample space.

So these 1, 2, 5 and 6 consists either a blue shirt or a black shirt.

The subset consists of all the outfits that do not have a white shirt.

So the correct options are :

1. (Choice A)

The subset consists of all the outfits that do not have a white shirt.

2. (Choice C)

The subset consists of all the outfits that have a black shirt.

5 0
2 years ago
Please help me wit dis part #2!!!
kow [346]

A)     The relationship between the amount of hours spent studying and the test scores increase with time in a positive direction showing a positive correlation.

B)     Y=8x+40

Y=8(3) +40

Y=24+40

Y= 64

C)      The 40 stands for the initial score the student can get without any studying


6 0
2 years ago
Trigonometry questions
trasher [3.6K]

We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.

11.

Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.

tan B = b/a

b = a tan B = 65.7 tan 28.9° = 36.3 m

12.

Similar story, boat at B, opposite b=3.5 m, rope c=12 m

sin B = b/c

B = arcsin b/c = arcsin (3.5/12) = 17.0°

13.

c=124 m, A=58°

sin A = a/c

a = c sin A = 124 sin 58 = 105.2 m

14.

That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so

cos A = b/c

A = arccos b/c = arccos (1.8/2.8) = 50.0°

15.

Not a right triangle, an isosceles triangle.  Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°.  We're after d=2b:

sin B = b/c

b = c sin B

d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm

Almost equilateral


4 0
3 years ago
Anyone mind helping me solve this inequality? Step by step
dlinn [17]

By decomposing the figure in simpler shapes, we will see that the total area is:

a = 180 cm²

<h3>How to find the area of the composite figure?</h3>

Remember that the area of a rectangle of width W and length L is:

A = L*W

And the area of a triangle with base B and height H is:

A = B*H/2.

Then, the upper part can be seen as a rectangle of length of 6cm and width of 6 cm, with two triangles on the sides, such that each triangle has a base of 3cm and a height of 6cm.

So the area of that part is:

A = 6cm*6cm + 2*(3cm*6cm/2) = 54cm²

Now, the bottom triangle has a base of 12 cm, and a height of:

15cm - 6cm = 9cm

Then its area is:

A' = 12cm*9cm/2 = 54cm²

This means that the total area of the figure is:

total area = 54cm² + 54cm² = 108cm²

If you want to learn more about area:

brainly.com/question/24487155

#SPJ1

5 0
1 year ago
Is the mean of 5 negative numbers positive or negative? explain
dimulka [17.4K]

Answer: Always negative

8 0
2 years ago
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