Answer:
Explanation:
The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:
The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:
Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.
The answer is, 25z^4+30z^3+29z^2+12z+4
Or z(z(z(25z+30)+29)+12)+4
Answer:
AC
Step-by-step explanation:
∆ABC ~ ∆DEF
AB/DE
∆ABC ~ ∆DEF
AC/DF
Answer: AC
Look at the problem and do it in order
I don’t know for sure but maybe 60?