Answer:
the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)
Step-by-step explanation:
since the variance S² of the batch follows a normal distribution , then for a sample n of 20 distributions , then the random variable Z:
Z= S²*(n-1)/σ²
follows a χ² ( chi-squared) distribution with (n-1) degrees of freedom
since
S² > 3.10 , σ²= 1.75 , n= 20
thus
Z > 33.65
then from χ² distribution tables:
P(Z > 33.65) = 0.02020
therefore the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)
1.
None of the households in the United States contain five children.
2.
The majority of the households in the United States, with at least one child, contain less than three children.
If thats wrong dont go off on me
~s9154499~
~Mia for short~
Well 6^2 is 36 so my best estimate is 6
Answer:
C. (x + 10)
Step-by-step explanation:
