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Ivahew [28]
3 years ago
9

Equivalent ???????????hh

Mathematics
2 answers:
olasank [31]3 years ago
4 0
The 3rd one is the right answer because you have to isolate x
Delicious77 [7]3 years ago
4 0

3(x - 8) < 5x + 6 \\ 3x - 24 < 5x + 6 \\  - 24 < 5x - 3x + 6 \\  - 24 - 6 < 2x \\  - 30 < 2x \\  - 15 < x
x>-15
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What are two ways to rewrite the following expression?<br> 5 + b
Akimi4 [234]

Answer:

1(5+b) or 2+3+b

hope this helps

have a good day :)

Step-by-step explanation:

6 0
3 years ago
Here is where u can send it
Alecsey [184]

Step-by-step explanation:

what about now hope it helps

8 0
3 years ago
An unusually wet spring has caused the size of a mosquito population in some city to increase by ​8% each day. If an estimated ​
tatyana61 [14]

Answer:

The number of mosquitoes that will inhabit the city on May 25 is 4,471,200.

Step-by-step explanation:

Note: This question is not complete as some important figures and points are omitted. The complete question is therefore provided before answering the question as follows:

An unusually wet spring has caused the size of a mosquito population in some city to increase by ​8% each day. If an estimated ​180,000 mosquitoes are in the city on May 12​, find how many mosquitoes will inhabit the city on May 25. Use y= 18​0,000(1.08)x where x is number of days since May 2.

The explanation to the answer is now given as follows:

Given;

y = 18​0,000(1.08)x = 18​0,000 * 1.08 * x .................... (1)

Where;

y = Number of mosquitoes that will inhabit the city on May 25 = ?

x = Number of days since May 2 = 25 - 2 = 23

Substituting for x = 23 into equation (1), we have:

y = 18​0,000 * 1.08 * 23

y = 4,471,200

Therefore, the number of mosquitoes that will inhabit the city on May 25 is 4,471,200.

3 0
2 years ago
Water is pumped into a tank at a rate of r (t)=30(1−e− 0.16t) gallons per minute, where t is the number of minutes since the pum
Vlad1618 [11]

Answer:

The total volume of the water in the tank after 20 minutes = 1220 gallons

Step-by-step explanation:

Rate of water pumped into the tank  r (t) = 30 (1 - e^{-0.16 t} )

Initial volume of water in the tank = 800 gallons

The water in the tank after 20 minutes = Initial volume of water in the tank + Volume of water being pumped in the tank

V_{total} = V_{i} + V_{pump}

V_{pump} = \int\limits^a_b {r(t)} \, dt

Where a = 0 , b = 20

Put the value of r (t) in above equation we get

V_{pump} = \int\limits^a_b {30 (1 - e^{-0.16t} )} \, dt

V_{pump} = 30 [ t + \frac{e^{-0.16t} }{0.16} ]

V_{pump} = 30[ (20- 0) + \frac{1}{0.16}(e^{-0.16 (20)}- e^{0}  )

V_{pump} = 420 gallon

Now, total volume in the tank

V_{total} = V_{i} + V_{pump}

V_{total} = 800 + 420

V_{total} = 1220 \ gallon

Therefore the total volume of the water in the tank after 20 minutes = 1220 gallons

3 0
3 years ago
I need help please no need for step by step.
Klio2033 [76]
Sorry you dont have a picture so i can not help
4 0
2 years ago
Read 2 more answers
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