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3 years ago

15

Find the missing side lengths. Leave your answer in simplest radical form

2 answers:

RUDIKE [14]3 years ago

8 0

Sin60°=p/h
or,√3/2=5√3/x
x=10
p=5√3 , h=x=10. then b=y=?
From Pythagoras theorem,
b²=h²-p²
=(10)²- (5√3)²
=100 - 75
=25
b=5. So,x=10 and y=5

kumpel [21]3 years ago

5 0

X=10 and y=5 so it's the first option

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Stuck on this one please help

Mashutka [201]

Answer:

3

Step-by-step explanation:

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2 years ago

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How many solutions does the following equation have? ln(x2 + 4x − 5) = 0

lisov135 [29]

Alrighty
remember
$log_a(b)=c$ means $a^c=b$
and
$ln(x)=log_e(x)$
and
$x^0=1$ for all real values of x
so

$ln(x^2+4x-5)=0$ means
$log_e(x^2+4x-5)=0$ means
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1=x²+4x-5
minus 1 both sides
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3 years ago

A bag contains 5 2/5kg of sand. The bag has a hole in it. Every 10 minutes, 1 2/3kg of sand escapes from the bag. After 20 minut

fenix001 [56]

Quantify of sand in a bag =

$= \: 5 \frac{2}{5} \ \:$

$= \frac{(5 \times 5 +2) }{5}$

$= \frac{27}{5} \: kg$

Quantity of sand that escapes in every 10 minutes :-

$= 1 \frac{2}{3} kg$

Quantity of sand that will escape in 20 minutes :-

$= 1 \frac{2}{3} \times 2$

$= \frac{(3 \times 1 + 2)}{3} \times 2$

$= \frac{5}{3} \times 2$

$= \frac{10}{3}$

Quantity of sand that will remain in the sand bag :-

$= \frac{27}{5} - \frac{10}{3}$

$= \frac{(27 \times 3)}{15} - \frac{(10 \times 5)}{15}$

$= \frac{81}{15} - \frac{50}{15}$

$= \frac{31}{15}$

$= 2 \frac{1}{5} \: kg$

$therefore \: , \: 2 \frac{1}{5} \: kg \: sand \: is \: left \: in \: the \: bag \: .$

3 0

3 years ago