18 = .75x
/.75 /.75 (divide both sides by .75 to isolate x)
24 = x
24 total students
Hope this helps!
Answer:
15, 840.
Step-by-step explanation:
-HCM(GCM)
105's factor are 1, 3, 5, 7, <em>15</em>, 21, 35, 105.
125's factor are 1, 2, 3, 4, 5, 6, 8, 10, 12, <em>15</em>, 20, 24, 30, 40, 60, 120.
so, the answer is 15!
Mel should use the least common multiple to solve the problem
<u>Solution:</u>
Given, Mel has to put the greatest number of bolts and nuts in each box so each box has the same number of bolts and the same number of nuts.
We have to find that should Mel use the greatest common factor or the least common multiple to solve the problem?
He should use least common multiple.
Let us see an example, suppose 12 bolts and nuts are to be fit in 6 boxes.
Then, if we took H.C.F of 12 and 6, it is 6, which means 6 bolts and nuts in each box, but, after filling 2 boxes with 6 bolts and nuts, there will be nothing left, which is wrong as remaining boxes are empty.
So the remaining method to choose is L.C.M.
Hence, he should use L.C.M method.
ANSWER:
(y^2+1)+1=3
Hope it helps u! :)
