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dybincka [34]
3 years ago
5

2-[6÷2+{6×1/2+(7/2-3/2)}]​

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0

Answer:

-6

<em>hop</em><em>e</em><em> this</em><em> helps</em>

Step-by-step explanation:

2_(6÷2+(6*1/2+(7/2-3/2))) solve the ones in bracket first

(7/2-3/2)=2

2-(6÷2+(6×1/2+2))

6×1/2+2

6×1/2=3

3+2=5

<em>2</em><em>-</em><em>(</em><em>6</em><em>÷</em><em>2</em><em>+</em><em>5</em><em>)</em>

<em>6</em><em>÷</em><em>2</em><em>=</em><em>3</em>

<em>3</em><em>+</em><em>5</em><em>=</em><em>8</em>

<em>2</em><em>-</em><em>8</em>

<em>=</em><em>-</em><em>6</em>

professor190 [17]3 years ago
5 0

Answer:

-6

Step-by-step explanation:

2 - [6 ÷ 2 + {6 × 1/2 + (7/2 - 3/2)}] =

Follow the correct order of operations.

Do one step at a time and copy everything else each time, so you don't lose track of any operation.

= ​2 - [6 ÷ 2 + {6 × 1/2 + 4/2}]

= 2 - [6 ÷ 2 + {6 × 1/2 + 2}]

= 2 - [6 ÷ 2 + {3 + 2}]

= 2 - [6 ÷ 2 + 5]

= 2 - [3 + 5]

= 2 - 8

= -6

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Dinesh has been keeping track of his time at work over the past month. Answer the questions below using the information provided
Gala2k [10]

The total hours that Dinesh worked each week over the past month are as follows:

<h3>Dinesh's Time in Hours</h3>

                Total Hours

                   Worked

Week 1        37.500    

Week 2       36.071

Week 3      35.999

Week 4      34.570

Total          144.140

<h3>Data and Calculations:</h3><h3>Dinesh's Time in Hours</h3>

                Meetings  Administration   Project X -  Project X-  Total Hours

                                                               Design   Deliverables    Worked

Week 1        7¹/₄               4¹/₄                  23¹/₃              2²/₃

Week 2       4²/₃              2⁴/₇                  16¹/₃              12¹/₂

Week 3      3.50             3.83                9.33              19.33

Week 4      6.17                3.40                4.20              20.80

<h3>Conversion into Dinesh's Time in Hours (decimals)</h3>

                Meetings  Administration   Project X -  Project X-  Total Hours

                                                              Design   Deliverables    Worked

Week 1        7.250            4.250           23.333           2.667          37.500    

Week 2       4.667            2.571             16.333         12.500          36.071

Week 3      3.500            3.833              9.333          19.333         35.999

Week 4       6.170            3.400             4.200        20.800          34.570

Total        21.587            14.054            53.199        55.300         144.140

Thus, Dinesh's total hours worked for the past month was <u>144.140 hours</u>.

Learn more about calculating hours worked at brainly.com/question/17054097

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Paul [167]

yap mofos morning good

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3 years ago
In a recent study on world​ happiness, participants were asked to evaluate their current lives on a scale from 0 to​ 10, where 0
uysha [10]

Answer:

a) A response of 8.9 represents the 92nd ​percentile.

b) A response of 6.6 represents the 62nd ​percentile.

c) A response of 4.4 represents the first ​quartile.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5.9

Standard Deviation, σ = 2.2

We assume that the distribution of response is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) We have to find the value of x such that the probability is 0.92

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.92

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = 1.405\\x = 8.991 \approx 8.9

A response of 8.9 represents the 92nd ​percentile.

b) We have to find the value of x such that the probability is 0.62

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.62

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = 0.305\\x = 6.571 \approx 6.6

A response of 6.6 represents the 62nd ​percentile.

c) We have to find the value of x such that the probability is 0.25

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.25

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = -0.674\\x = 4.4172 \approx 4.4

A response of 4.4 represents the first ​quartile.

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