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3 years ago

For the equation, y = -4X - 5, tell whether it's graph passes through the first quadrant. Explain how you know

2 answers:

maks197457 [2]3 years ago

4 0

it does not pass through quadrant I.

Both the slope and Y value are negative.

Meaning this equation goes up to the left and down right.

(you can use a graphing calculator (if you have one.) and plug this equation into the GRAPH.) It will show you the line.

Alina [70]3 years ago

3 0

It doesn't passes because:

1) It has a negative gradient
2) It has a y-intercept of -5

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6y-5=11 what the answer I’m having a hard time finding it

QveST [7]

6y-5=11

Move -5 to the other side. Sign changes from -5 to +5.

6y-5+5=11+5

6y=11+5

6y=16

Divide by 6 for both sides to get y by itself.

6y/6=16/6

Cross out 6 and 6, divide by 6 and then becomes 1*1*y=y

y=16/6

Reduce 16/6 by dividing by 2

16/2=8

6/2=3

Answer: y=8/3 or y=2 2/3

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3 years ago

Read 2 more answers

Please help with the answer :(

Alenkinab [10]

Answer:

Step-by-step explanation:

3/4

4 0

3 years ago

6th grade math! Help me if you can! C;

xxMikexx [17]

<h3><u>Original Rate</u> <u>Unit Rate</u> </h3>

90 Miles 45 Miles

2 Hours 1 Hour

Answer: <u><em>The Train travels 45 miles in one hour.</em></u>

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<em><u>Give Brainliest If You Please</u></em>

5 0

3 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0

1 year ago

the length of a table is 6 feet. on a scale drawing, the length is 2 inches. write three possible scales for the drawing

butalik [34]

2 inches : 6 feet is the same as 1 inch : 3 feet
It could also be written:
1 inch : 36 inches
1 foot : 36 feet

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3 years ago