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Harlamova29_29 [7]
3 years ago
5

For the equation, y = -4X - 5, tell whether it's graph passes through the first quadrant. Explain how you know

Mathematics
2 answers:
maks197457 [2]3 years ago
4 0
it does not pass through quadrant I.

Both the slope and Y value are negative.

Meaning this equation goes up to the left and down right.

(you can use a graphing calculator (if you have one.) and plug this equation into the GRAPH.) It will show you the line.
Alina [70]3 years ago
3 0
It doesn't passes because:

1) It has a negative gradient
2) It has a y-intercept of -5
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If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
Jobisdone [24]
The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
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3 years ago
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makkiz [27]
There were 70 people who took the survey. 210 / 70 = 3. So, whatever 40 - 10 is, if we multiply by three, we get the answer. 40 - 10 = 30. 30 x 3 = 90. Simple as that. Hope I could help!
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Find the upper limit for the zeros of the function P(x)=4x^4+8x^3-7x^2-21x-9
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Answer:

OPTION B - 2

Step-by-step explanation:

What is the upper limit for the zeros of the function P(x) = 4x^4 + 8x^3 - 7x^2 - 21x - 9. Ans: 2 is an upper limit. Use synthetic division. and the remainder are all positive, 2 is an upper limit.

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Answer:

7^3×1/(16)^9...........

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4 years ago
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maw [93]

Answer:

B = 5:00

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