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Harlamova29_29 [7]
3 years ago
5

For the equation, y = -4X - 5, tell whether it's graph passes through the first quadrant. Explain how you know

Mathematics
2 answers:
maks197457 [2]3 years ago
4 0
it does not pass through quadrant I.

Both the slope and Y value are negative.

Meaning this equation goes up to the left and down right.

(you can use a graphing calculator (if you have one.) and plug this equation into the GRAPH.) It will show you the line.
Alina [70]3 years ago
3 0
It doesn't passes because:

1) It has a negative gradient
2) It has a y-intercept of -5
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Solution :

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$=t_{n_1+n_2-2,0.025} \times \left( s \sqrt{\frac{1}{n_1}+\frac{1}{n_2}}$

$s^2 = \frac{(n_1-1)S_1^2+(n_2-1)S^2_2}{n_1+n_2-2}$

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$M.E. = 1.99 \times 3.03 \times \sqrt{\frac{1}{39}+\frac{1}{37}}$

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Therefore, 95% CI = [(25.90-27.70) - 1.4 , (25.90-27.70) + 1.4]

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Therefore, the lower bound is -3.2

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