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Temka [501]
3 years ago
5

Find the area of the Compound shape The answer is 89 m^2 I just need the steps....

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

Area of semi-circle is \frac{\pi r^2}{2} ≈ \frac{22}{7} × 4² ÷ 2 ≈ 25 cm²

Area of square is 8² = 64 cm²

Total area is 25 + 64 = 89 cm²

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Write down in terms of n, an expression for the nth term
Nimfa-mama [501]

Answer:

a_{n} = - 7n - 1

Step-by-step explanation:

There is a common difference between consecutive terms , that is

- 15 - (- 8) = - 22 - (- 15) = - 29 - (- 22) = - 36 - (- 29) = - 7

This indicates the sequence is arithmetic with nth term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 8 and d = - 7 , then

a_{n} = - 8 - 7(n - 1) = - 8 - 7n + 7 = - 7n - 1

7 0
3 years ago
Someone please explain this​
jeyben [28]

Answer:

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the second one is the third one

7 0
3 years ago
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Please help!!!!!!!!!
Musya8 [376]

Answer:

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Step-by-step explanation:

7 0
3 years ago
I will mark as the brainliest answer
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5 0
3 years ago
the equation of line cd is y = 3x − 3. write an equation of a line perpendicular to line cd in slope-intercept form that contain
liberstina [14]

Answer:

The required equation is y=-\frac{1}{3}x+2.

Step-by-step explanation:

The equation of line cd is

y=3x-3

Slope intercept form of a line is

y=mx+b

Where, m is slope and b is y-intercept.

Slope of line cd is 3.

The product of slopes of two perpendicular lines is -1.

m_1\times m_2=-1

3\times m_2=-1

m_2=-\frac{1}{3}

Therefore slope of perpendicular line is -\frac{1}{3}.

Point slope form of a line is

y-y_1=m(x-x_1)

Slope of perpendicular line is -\frac{1}{3} and line passing through the point (3,1).

y-1=-\frac{1}{3}(x-3)

y=-\frac{1}{3}x+1+1

y=-\frac{1}{3}x+2

Therefore the required equation is y=-\frac{1}{3}x+2.

4 0
3 years ago
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