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3 years ago

What are two other forms of writing for 8.517?

Mathematics

2 answers:

galina1969 [7]3 years ago

7 0

Answer:

8517/1000

Eight and five hundred seventeen thousandths

DM me with any other questions!

Rzqust [24]3 years ago

5 0

Answer:

Mixed Number : 8 517/1000

Improper Fraction : 8517/1000

Step-by-step explanation:

Hope this helps :)

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Your little brother just learned how to flip and catch a coin. He believes that by catching the coin in mid-air, he can influenc

coldgirl [10]

<h2>Answer explanation:</h2>

If a coin is fair then it has two faces , one is heads and the another is tails.

The probability getting any favorable outcomes is given by the formula :-

$\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}$

So the factor effecting probability is just the number of favorable outcomes and total outcomes.

If a coin is tossed then the probability of getting heads will be :-

$P(H)=\dfrac{1}{2}=0.5=50\%$

To get heads always this should be 1 , which can be happen if number of favorable outcomes is equal to total outcomes.

i.e. Number of heads = Number of total outcomes, this means coin should be biased.

Catching the coin in mid-air can never be a factor for this.

Therefore, the little brother's theory is false.

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3 years ago

$650 is invested in an account at 3% simple interest per year. Write an explicit formula representing the account balance in any

mixer [17]

The correct answer is 1,950

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3 years ago

The faces on a number cube are labled 1,2,2,3,4, and 5the number cube is rolled 114 times how many times would you expect the nu

Mrac [35]

Given:

The faces on a number cube are labeled 1,2,2,3,4, and 5.

The number cube is rolled 114 times.

To find:

How many times would you expect the number 2 to appear?

Solution:

We have,

Total outcomes = 1,2,2,3,4, and 5.

Number of total outcomes = 6

Favorable outcomes = 2 and 2

Number of favorable outcomes = 2

The probability of getting 2 is:

$P(2)=\dfrac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}$

$P(2)=\dfrac{2}{6}$

$P(2)=\dfrac{1}{3}$

Now, the expected number of times when 2 to appear is:

$E(x)=114\times P(2)$

$E(x)=114\times \dfrac{1}{3}$

$E(x)=38$

Therefore, the expected number of times is 38.

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2 years ago

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Ahat [919]

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3 years ago

Please help me with this I will give brainliest please answer it right

weeeeeb [17]

Answer:

Step-by-step explanation:

RR, RY, RG, RP, YY, YG, YP, YR, GG,GP, GR, PP, PR, PY, PG.

All combinations of the four colors are provided in Option A as written out above. The other options are missing combinations.

I hope I helped, Would appreciate Brainliest! ;)

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3 years ago