Answer:
The three major phases of matter are Solid, Liquid, and Gas. But there is also Plasma
Answer : The hydrocarbons containing a saturated carbon ring are called Aliphatic cyclic hydrocarbon.
Explanation :
As the organic compounds are classified into two categories that is acyclic (aliphatic) and cyclic (aromatic) compounds.
Acyclic compounds : It is an open chain compound with linear structure.
Cyclic compounds : It is a closed chain compound having a carbon ring structure.
Hydrocarbon : It is an organic compound that contains only hydrogen and the carbon atoms. They are of two types which are saturated hydrocarbon and unsaturated hydrocarbon.
Saturated hydrocarbon : These are the compounds which containing single bonds between the carbon-carbon atoms. In saturated compounds, there are more number of hydrogen bonded with the carbon atom.
Unsaturated hydrocarbon : These are the compounds which containing double and triple bonds between the carbon-carbon atoms. In unsaturated compounds, there are less number of hydrogen bonded with the carbon atom.
Hence, the hydrocarbons containing a saturated carbon ring are called Aliphatic cyclic hydrocarbon.
4.14x10^-3 per minute
First, calculate how many atoms of Cu-61 we initially started with by
multiplying the number of moles by Avogadro's number.
7.85x10^-5 * 6.0221409x10^23 = 4.7273806065x10^19
Now calculate how many atoms are left after 90.0 minutes by subtracting the
number of decays (as indicated by the positron emission) from the original
count.
4.7273806065x10^19 - 1.47x10^19 = 3.2573806065x10^19
Determine the percentage of Cu-61 left.
3.2573806065x10^19/4.7273806065x10^19 = 0.6890455577
The formula for decay is:
N = N0 e^(-λt)
where
N = amount left after time t
N0 = amount starting with at time 0
λ = decay constant
t = time
Solving for λ:
N = N0 e^(-λt)
N/N0 = e^(-λt)
ln(N/N0) = -λt
-ln(N/N0)/t = λ
Now substitute the known values and solve:
-ln(N/N0)/t = λ
-ln(0.6890455577)/90m = λ
0.372447889/90m = λ
0.372447889/90m = λ
0.00413830987 1/m = λ
Rounding to 3 significant figures gives 4.14x10^-3 per minute as the decay
constant.
You have completely built 4 cars. You still have 2 doors and 3 bodies left.
Oxygen difluoride, OF2 , is a polar molecule because it has a bent molecular geometry. This molecular geometry ensures that the dipole moments associated with the oxygen - fluoride bonds do not cancel each other out to produce a nonpolar molecule.