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vaieri [72.5K]
3 years ago
10

Photo attached, please help me if you can :(

Chemistry
1 answer:
mylen [45]3 years ago
7 0

Answer:

I'm pretty sure the ionic structure is C, sorry this is only one answer tho : , (

Explanation:

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calculate the number of coulombs of positive charge in 250cm 3 of (neutral) water. (hint: a hydrogen atom contains one proton; a
Sidana [21]

Number of coulombs of positive charge in 250cm^3 water is 1.3×10^7 C

The volume of 250 cm^3 corresponds to a mass of 250 g since the density of water is 1.0 g/cm^3

This mass corresponds to 250/18 = 14 moles since the molar mass of water is 18. There are ten proton (each with charge q = +e) in each molecule of H_{2}O So,

Q = 14NA  q =14(6.02×10^23)(10)(1.60×10^−19C) = 1.3×10^7 C.

Mass is the quantity of matter in a physical body. It is also a measure of the body's inertia, the resistance to acceleration when a net force is applied. An object's mass also determines the strength of its gravitational attraction to other bodies.

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3 0
1 year ago
Ion Formed of Cl , Te
Sidana [21]
Chlorine will have a -1 charge and Tellurium has a -2 charge when they are ions. 
3 0
3 years ago
If 33.6 grams of kcl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass? 21.2% kc
trapecia [35]
Ms ( mass of solute): 33,6g
mss (mass of solution): 33,6+192g = 225,6g
__________________
C = ms/mss × 100%
C = 33.6/225.6 × 100%
C = 14,89% ≈ 14,9%

:•)
4 0
3 years ago
Read 2 more answers
You want to determine the concentration of a solid solute dissolved in a specified volume of liquid solvent which of the followi
Natali [406]
Generally, chemists prefer to use morality (B) because it only invovles measuring the final volume of the solution and amount of moles of the solute

Hope this helps
6 0
3 years ago
Read 2 more answers
part of the SO2 that is introduced into the atmosphere by combustion of sulfur containing compounds ends up being converted to s
alisha [4.7K]

Answer:

5 mol.

Explanation:

Equation of the reaction

2SO2 + 2H2O + O2 --> 2H2SO4

By stoichiometry, 2 moles of SO2 reacted with 2 moles of water and 1 mole of O2 to give 2 mole of sulphuric acid.

Number of moles:

5.0 mol SO2

4.0 mol O2

20.0 mol H2O

Calculating the limiting reagent,

5 mol of SO2 * 1 mol of O2/2 mol of SO2

= 2.5 mol of O2(4 mol of O2 is present)

5 mol of SO2 * 2 mol of H2O/2 mol of SO2

= 5 mol of H2O(20 mol of H2O)

SO2 is the limiting reagent.

Therefore, number of moles of H2SO4 = 5 mol of SO2 * 2 mol of H2SO4/2 mol of SO2

= 5 mol of H2SO4.

5 0
3 years ago
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