Answer:
angle b is 62 degrees. This is because if we solve for x, by putting the 2 equations equal to each other(because they are vertical angles), than we figure out that x=6. Now plug that into angle b's equation, and you get 62 degrees.
Step-by-step explanation:
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:
eh width = 103.5 inches
Step-by-step explanation:
x = width
Length = (x/2 - 5 )*6
so 384=x+3x-30
414=4x
x=414/4=103.5 inches
Pm+4=4(4)+4=20
The value is 20.
Hope this helps
