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anastassius [24]
3 years ago
12

Does anybody know what the answers are

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0

5=s

6=e

7=I

8=t

9=h



15=t

16=t

17=w

18=d

19=n

20=u

21=t

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3g + 4g<br> How do you this? Is there a simple way??
soldi70 [24.7K]
They're like terms. So it will be 7g as you plus the co-efficient together and you 7 and the g you add it to it.
5 0
3 years ago
Find a cartesian equation for the curve. r = 9 sin(θ)
Paul [167]
For this case we have the following equation:
 r = 9 sin (θ)
 In addition, we have the following change of variables:
 y = r * sine (θ)
 Rewriting the equation we have:
 r = 9 sin (θ)
 r = 9 (y / r)
 r ^ 2 = 9y
 On the other hand:
 r ^ 2 = x ^ 2 + y ^ 2
 Substituting values:
 x ^ 2 + y ^ 2 = 9y
 Rewriting:
 x ^ 2 + y ^ 2 - 9y = 0
 Completing squares:
 x ^ 2 + y ^ 2 - 9y + (-9/2) ^ 2 = (-9/2) ^ 2
 Rewriting:
 x ^ 2 + 1/4 (2y-9) ^ 2 = 81/4
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 Answer:
 
The Cartesian equation is:
 
4x ^ 2 + (2y-9) ^ 2 = 81
6 0
2 years ago
I’m not sure which one it is.
Fofino [41]

Answer: the answer is A) AC~=FC

Step-by-step explanation:

to answer that both triangles are congruent using SSS (Side-side-side) postulate, you have to show that each corresponding side is the same.

4 0
2 years ago
The cafeteria manager took a survey of the third grade students and found that 83 of 127 students said they did not want hot dog
Natalka [10]
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Shown work below
You're welcome ;)

6 0
3 years ago
Read 2 more answers
The table of values represents an exponential function f(x).
Ostrovityanka [42]

Answer:

-3.98 (nearest hundredth)

Step-by-step explanation:

The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:

\dfrac{f(b)-f(a)}{b-a}

Given interval:  -2 ≤ x ≤ 2

\implies a = -2

\implies b = 2

\implies f(a) = f(-2)=16

\implies f(b) =f(2)= \dfrac{1}{16}

Substituting the values into the equation:

\begin{aligned}\implies \textsf{rate of change} & =\dfrac{\frac{1}{16}-16}{2-(-2)}\\\\ & = \dfrac{-\frac{255}{16}}{4}\\\\ & = -\dfrac{255}{64}\\\\ & = -3.98\: \sf (nearest\:hundredth)\end{aligned}

7 0
2 years ago
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