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anastassius [24]

3 years ago

12

Does anybody know what the answers are

1 answer:

Oksi-84 [34.3K]3 years ago

8 0

5=s

6=e

7=I

8=t

9=h

15=t

16=t

17=w

18=d

19=n

20=u

21=t

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A triangle ABC is inscribed in the circle, (ABC = 65° and AB=AC. Find (BDC.

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Answer:

∠BDC=50°

Step-by-step explanation:

∠BDC=∠A[angles at the same segment)

∠A= 180-(65+65)=180-130= 50°

so, ∠BDC=50°

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A secant and a tangent to a circle intersect in a 42-degree angle. The two arcs of the circle intercepted by the secant and the

Amanda [17]

Answer:

The measure of the third arc is $150\°$

Step-by-step explanation:

step 1

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

in this problem

Let

x----> the greater arc of the circle intercepted by the secant and the tangent

y----> the smaller arc of the circle intercepted by the secant and the tangent

$42\°=\frac{1}{2}(x-y)$

$84\°=(x-y)$ ----> equation A

$\frac{x}{y}=\frac{7}{3}$

$x=\frac{7}{3}y$ -----> equation B

Substitute equation B in equation A and solve for y

$84\°=(\frac{7}{3}y-y)$

$84\°=(\frac{4}{3}y)$

$y=3*84\°/4=63\°$

Find the value of x

$x=\frac{7}{3}(63\°)=147\°$

step 2

Find the measure of the third arc

Let

z------> the measure of the third arc

we know that

$x+y+z=360\°$ -----> complete circle

substitute the values and solve for z

$147\°+63\°+z=360\°$

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3 years ago

Given a leading coefficient of 8, polynomial roots of 1 & 2, and the known point on the graph (4,5). Write an equation that

m_a_m_a [10]

Given:

The leading coefficient of a polynomial is 8.

Polynomial roots are 1 and 2.

The graph passes through the point (4,5).

To find:

The 3rd root and the equation of the polynomial.

Solution:

The factor form of a polynomial is:

$y=a(x-c_1)(x-c_2)...(x-c_n)$

Where, a is a constant and $c_1,c_2,...,c_n$ are the roots of the polynomial.

Polynomial roots are 1 and 2. So, $(x-1)$ and $(x-2)$ are the factors of the polynomial.

Let the third root of the polynomial by c, then $(x-c)$ is a factor of the polynomial.

The leading coefficient of a polynomial is 8. So, a=8 and the equation of the polynomial is:

$y=8(x-1)(x-2)(x-c)$

The graph passes through the point (4,5). Putting $x=4,y=5$ , we get

$5=8(4-1)(4-2)(4-c)$

$5=8(3)(2)(4-c)$

$5=48(4-c)$

Divide both sides by 48.

$\dfrac{5}{48}=4-c$

$c=4-\dfrac{5}{48}$

$c=\dfrac{192-5}{48}$

$c=\dfrac{187}{48}$

Therefore, the 3rd root on the polynomial is $\dfrac{187}{48}$ .

8 0

2 years ago