25 over 100 as a percent is 25% and 25 over 100 as a decimal is .25
You're given the slope of the line and a point thru which the line passes. So it makes sense to use the point-slope form of the equation of a straight line: if the point is (a,b) and the slope is m, then
y-b=m(x-a). You'd then solve this for y to obtain the equation in slope-intercept form.
On the other hand, if you're asked to write the equation in slope-intercept form, starting with the general form of this equation may be faster: y=mx+b.
Substitute the given values for x and y (which are 25 and -9) and m (which is (2/5). Solve the resulting equation for b (the y-intercept).
Then write the finished equation: y=( ? )x + b, where b is the y-intercept you've just found.
With the information given, we deduce that the parabola is
![y=-(x-3)^2+4 = -(x^2-6x+9)+4 = -x^2+6x-5](https://tex.z-dn.net/?f=y%3D-%28x-3%29%5E2%2B4%20%3D%20-%28x%5E2-6x%2B9%29%2B4%20%3D%20-x%5E2%2B6x-5)
Reflecting a function over the x axis means to change its sign. After the reflection, the parabola becomes
![y=x^2-6x+5](https://tex.z-dn.net/?f=y%3Dx%5E2-6x%2B5)
And to shift down a function, you subtract the shift from the equation: the equation becomes
![y=x^2-6x+5-2=x^2-6x+3](https://tex.z-dn.net/?f=y%3Dx%5E2-6x%2B5-2%3Dx%5E2-6x%2B3)
Similarly, the other function is reflected over the x axis (sign change) and shifted up 3 (add 3 to the equation):
![|x+2|\mapsto -|x+2|\mapsto -|x+2|+3](https://tex.z-dn.net/?f=%7Cx%2B2%7C%5Cmapsto%20-%7Cx%2B2%7C%5Cmapsto%20-%7Cx%2B2%7C%2B3)
In order to compute the y intercept, we simply have to evaluate the functions at x=0: for the parabola we have
![y(0)=3](https://tex.z-dn.net/?f=y%280%29%3D3)
For the other function, we have
![y(0)=-|2|+3=-2+3=1](https://tex.z-dn.net/?f=y%280%29%3D-%7C2%7C%2B3%3D-2%2B3%3D1)
At= -5(1/2)
at= -2.5
v= u + at
v= 2 + (-2.5)
v= -0.5