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3 years ago

Evaluate this integral. I'm not sure how to evaluate integrals with absolute values.

Mathematics

1 answer:

SOVA2 [1]3 years ago

6 0

Answer:

Step-by-step explanation:

The first step is to understand what the integrand looks like. (See the graph below.)

It is -1 for x < 0 and +1 for x > 0. Thus, the value of this integral is ...

$\int\limits^0_{-1} {-1} \, dx + \int\limits^2_0 {1} \, dx=-1+2=1$

_____

Essentially, you treat the absolute value as a piecewise linear function. This is the same way you treat an absolute value in any equation or inequality.

Here, this means you divide the integral into two parts: one where the integrand is -x/x, and one where it is +x/x.

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The product of two of three numbers is 7.8. if one number is 3/5, find the other number ( if you don't know please don't answer)

yarga [219]

Answer: 13,I

Step-by-step explanation:

set the 3 number is 3/5, x,y

product of them

3 /5 xy = 7:6

xy = 7:6 x 5 /3

Xy = 13

So the two number is 13, 1

Step-by-step explanation: hope this helped, Meow!

3 0

2 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

3 years ago

Help please I’m trying to find value of x and y. i need to write out the problem

Zanzabum

The answer is x=4.5 and y=1 they are dilated by multiplying 3

8 0

2 years ago

Please help me solveeeee

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

I think the only way you can solve this is to assume that <R means PRT in the given ratio. If I am wrong, I don't think the problem can be solved.

Find <T

Let <T = x

and <PRT = 3x

KLMN is a Parallelagram and therefore two adjacent angles are supplementary.

<PRT + <T = 180 degress

3x + x = 180 degrees

4x = 180

x = 45

So <T = 45

<PRT = 3*45 = 135

If RD is perpendicular to PS then <PDR = 90o

Here's the trick.

RD is also Perpendicular to RT

<MRD + <MRT = 90

<MRT = 180 - 90 - <T

<MRT = 180 - 90 - 45

<MRT = 45

Here comes your answer

=================

<MRD + MRT = 90

<MRD + 45 = 90

<MRD = 45

====================

Note: you must ignore everything to do with the diagram. It is not drawn to scale and the letters are not the same as in the question. The only thing you use is that the figure is a ||gm

8 0

3 years ago

How do I write 208,000,478 in expanded form

Rama09 [41]

200,000,000

8,000,000

478

all added together

4 0

3 years ago

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