4x²+4x-35=0 factor: (2x+7)(2x-5)=0 2x+7=0, or 2x-5=0 2x=-7 or 2x=5 x=-3.5 or x=2.5
I don't see any rounding necessary in this case.
when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b. in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way: 2 -5
2 7 then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.
if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right.
