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gizmo_the_mogwai [7]
3 years ago
14

A ball of radius 13 has a round hole of radius 9 drilled through its center.

Mathematics
1 answer:
GREYUIT [131]3 years ago
7 0

Answer:

Step-by-step explanation:

Given

radius of sphere R=13\ units

Hole is drilled with radius r=9\ units

Now this drilled hole will be in the form of Cylinder with height equals to diameter of sphere thus

Volume of drilled hole is

V_d=\pi \cdot r^2\cdot h

V_d=\pi \cdot (9)^2\cdot 26

V_d=2106\pi

Volume of Sphere

V_s=\frac{4}{3}\pi R^3

V_s=\frac{4}{3}\pi (13)^3

V_s=2929.33\pi

Remaining volume V_{remaining}=2929.33\pi -2106\pi =823.33\pi

V_{remaining}=2586.90\ units^3

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Answer:

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In this question:

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