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Dennis_Churaev [7]
3 years ago
7

Which value for x makes the sentence true?

Mathematics
2 answers:
KiRa [710]3 years ago
7 0
D. x = 5 because 10x+ -3x=35+3x+-3x
vekshin13 years ago
4 0
The answer is D. x=5
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Part A<br> How can you determine whether JKL = PQR?<br><br> Part B<br> Is JKL = PQR
kotegsom [21]

Answer:

JKL = PQR and JKL = PQR

Step-by-step explanation:

7 0
3 years ago
Discrete Math
andrezito [222]

Answer:

Part c: Contained within the explanation

Part b: gcd(1200,560)=80

Part a: q=-6         r=1

Step-by-step explanation:

I will start with c and work my way up:

Part c:

Proof:

We want to shoe that bL=a+c for some integer L given:

bM=a for some integer M and bK=c for some integer K.

If a=bM and c=bK,

then a+c=bM+bK.

a+c=bM+bK

a+c=b(M+K) by factoring using distributive property

Now we have what we wanted to prove since integers are closed under addition.  M+K is an integer since M and K are integers.

So L=M+K in bL=a+c.

We have shown b|(a+c) given b|a and b|c.

//

Part b:

We are going to use Euclidean's Algorithm.

Start with bigger number and see how much smaller number goes into it:

1200=2(560)+80

560=80(7)

This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.

Part a:

Find q and r such that:

-65=q(11)+r

We want to find q and r such that they satisfy the division algorithm.

r is suppose to be a positive integer less than 11.

So q=-6 gives:

-65=(-6)(11)+r

-65=-66+r

So r=1 since r=-65+66.

So q=-6 while r=1.

3 0
3 years ago
Please help me with this math problem
elena55 [62]

When a tangent line (13.5 cm) and a secant (lines x + 8.45 cm) intersect then:


tangent line^2 = 8.45 * (8.45 + x)


13.5^2 = 71.4025 + 8.45 x


182.25 -71.4025 = 8.45x


8.45 x = 110.8475


x = 13.1180473373


x = 13.1 (rounded)


Source:

1728.com/circangl.htm




4 0
3 years ago
Solve for all values of y<br> in simplest form.<br><br> ∣y−12∣=16
Reil [10]

Answer:

y=-4; y=28

Step-by-step explanation:

The way I like to think about it, with absolute value meaning the distance is

"find which number are 16 apart from 12". Which means 28 (to the right) or -4 (to the left).

More formally, applying the definition of absolute value,

|y-12|=16 \leftrightarrow y-12=\pm16\\y-12=-16 \rightarrow y=-4\\y-12=+16 \rightarrow y=28

5 0
2 years ago
How to find zeros of a quadratic function <br> example<br> f(x)=x^3+2x^2-25x-50
goblinko [34]

Answer:

Step-by-step explanation:

x=2,−5,5

7 0
2 years ago
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