Answer:

Step-by-step explanation:
The surface area of a square pyramid is the sum of the area of the squared base + 4 times the area of each triangular face, therefore:

where:
is the area of the base, where
L is the length of the base
is the area of each triangular face, where
h is the height of the face
Substituting,

For the model in this problem,
L = 12
h = 8
Therefore, the surface area here is:

Rewriting the left hand side,
csc²t - cost sec t
= (1/sin²t)-(cost)(1/cost)
= 1/sin²t - 1
= 1/sin²t - sin²t/sin²t
= (1-sin²t)/sin²t
= cos²t/sin²t
= cot²t
<span>Find force,
9.8 m/s2 x 5.24 kg = </span><span>51.352 N </span>
Find work,
<span><span>51.352 N x 1.63 m= </span><span>83.70 N*m
</span>Example:
To solve this given word problem we can first identify the given and the apt formula to use in this phenomenon: Given: Force = 4, 500 N = 4, 500 kg-m/s^2 Acceleration = 5 m/s^2 </span>
<span>Formula: f=ma </span>
<span>Derivation: m = f/a </span>
<span>Solution: </span><span><span>
1. </span>M = f/a</span> <span><span>
2. </span>M = 4,500 kg-m/s^2 / 5 m/s^2</span> <span><span>
3. </span>M = 900 kg </span>
<span>Hence, the object’s mass is </span>900 kg.<span>
</span>
Answer:
I'm confused what is the question?
Step-by-step explanation: