Answer:
How to factor out a polynomial with a 3rd degree-• well here is a For example, let G(x) = 7x³ – 125. Then factoring this third degree polynomial relieve on a differences of cubes as follows: (2x – 5) (4x² + 20x + 25), where ²x is the cube-root of 8x³ and 5 is the cube-root of 1256
2t-2=26
first you would add 2 to both sides
that equals 2t=28
then you would divide both sides by two
that would give you
t= 14
Therefore, the measures of the angles in triangle ABC is as follows:
- m∠A 73.7°, m∠B = 16.3°, m∠C = 90°
<h3>How to find angles of right triangle?</h3>
The measure of the angles in the right triangle can be found as follows:
Using trigonometric ratios,
sin ∅ = opposite / hypotenuse
sin ∅ = 7 / 25
∅ = sin ⁻¹ 0.28
∅ = 16.2602047083
∅ = 16.3°
Hence,
m∠B = 16.3°
m∠C = 90°
m∠A = 180 - 90 - 16.3 = 73.7°
learn more on right triangle here: brainly.com/question/27899600
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