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4 years ago

How do I solve by using system of elimination?

Mathematics

1 answer:

Nikitich [7]4 years ago

6 0

You eliminate or ‘take away’ the answers that you know or think that r wrong. The last answer that’s left is your answer.

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Find the length of molding needed for a 10'5" by 9'8" floor

disa [49]

Perimeter = 2(length + width)
p = 2(10'5" + 9'8")
p = 2(19'13")
p = 38'26"

26" = 2'4"

So...
38' + 2'4" = 40' 4" for the perim,eter

4 0

3 years ago

How can percents describe a change in area?

Marianna [84]

Divide the change by the initial number to get a fraction and multiply by 100% to get a percent. The percent you get will describe the change in area in the mathematical language of numbers.

7 0

3 years ago

What is x? <br> -6(9x+5) -3x+4x= -408+x

fredd [130]

X=-53x+378, if you need explanation used ask me.

7 0

4 years ago

2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

4 years ago

Find the mean and the median of this data set: 8, 6, 6, 3, 55, 7, 5, 2. The mean is and the median is .

Sonja [21]

Answer:

Mean: 11.5 Median: 6

Step-by-step explanation:

For the mean find the average by adding all of the numbers up and dividing by the number of numbers in the set.

For the median arrange the numbers in order of least to greatest then find the middle number if there is two add them together and divide by two.

7 0

3 years ago