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Diano4ka-milaya [45]
4 years ago
9

A sequence starts 1, 4, 9, 16 ... The nth term is n^2. Use this fact to find the nth term of the following sequences: a) 2, 5, 1

0, 17 b) 2, 8, 28, 32

Mathematics
1 answer:
OleMash [197]4 years ago
3 0

Answer:

n²+1

2n²

Step-by-step explanation:

We can see that 2, 5, 10, and 17 becomes 1, 4, 9, and 16 when we subtract 1.

So it adds 1. The nth will be n² + 1.

2, 8, 18, and 32 is the double of n². 1, 4, 9, and 16 are their half.

So the nth term becomes 2n².

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Keith_Richards [23]

Answer:

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Step-by-step explanation:

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Y en la parte del 2020 se ve que este en la mitad de 800 y 700 considerando el calculo anterior por lo que daría 750 cds en 2020

6 0
1 year ago
Given that f(x) =
Alex73 [517]

Answer:

Answer is b or 10.

Step-by-step explanation:

The reason for this is that you will just plug in all the answers in x and the answer has to match 15.

So...

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6 0
3 years ago
Read 2 more answers
Write a two-column proof. Given: line BD bisects angle CBE. Prove: angle ABD approximately equal to angle FBD.
ale4655 [162]

Answer:

The proof is derived from the summarily following equations;

∠FBE + ∠EBD = ∠CBA + ∠CBD

∠FBE + ∠EBD = ∠FBD

∠CBA + ∠CBD = ∠ABD

Therefore;

∠ABD ≅ ∠FBD

Step-by-step explanation:

The two column proof is given as follows;

Statement {}                                       Reason          

\underset{BD}{\rightarrow} bisects ∠CBE {}                            Given

Therefore;

∠EBD ≅ ∠CBD  {}                              Definition of angle bisector

∠FBE ≅ ∠CBA {}                                Vertically opposite angles are congruent

Therefore, we have;

∠FBE + ∠EBD = ∠CBA + ∠CBD {}     Transitive property

∠FBE + ∠EBD = ∠FBD {}                    Angle addition postulate

∠CBA + ∠CBD = ∠ABD {}                   Angle addition postulate

Therefore;

∠ABD ≅ ∠FBD        {}                          Transitive property.

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3 years ago
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5 0
3 years ago
Find the value of x<br><br> 3/4 x-4=8
Vesna [10]

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Step-by-step explanation:

Solve for   x  by simplifying both sides of the equation, then isolating the variable.  :)

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