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Diano4ka-milaya [45]
3 years ago
9

A sequence starts 1, 4, 9, 16 ... The nth term is n^2. Use this fact to find the nth term of the following sequences: a) 2, 5, 1

0, 17 b) 2, 8, 28, 32

Mathematics
1 answer:
OleMash [197]3 years ago
3 0

Answer:

n²+1

2n²

Step-by-step explanation:

We can see that 2, 5, 10, and 17 becomes 1, 4, 9, and 16 when we subtract 1.

So it adds 1. The nth will be n² + 1.

2, 8, 18, and 32 is the double of n². 1, 4, 9, and 16 are their half.

So the nth term becomes 2n².

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What is a formula for the nth term of a given sequence
IceJOKER [234]

Answer:

a_n=-12-4(n-1)

Step-by-step explanation:

The given sequence is

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The first term of this sequence is a_1=-12.

The common difference is

d=-16--12

d=-16+12=-4

The nth term of this arithmetic sequence is;

a_n=a_1+d(n-1)

We substitute the values for the first term and the common difference to obtain;

a_n=-12-4(n-1)

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3 years ago
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Answer:

Step-by-step explanation:

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7 0
3 years ago
The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505

0.1505 = 15.05% probability that the hockey team wins 6 games in November

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