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algol [13]
4 years ago
11

20 POINTS PLEASE HELP

Mathematics
1 answer:
Rom4ik [11]4 years ago
8 0
What are the measurements of the container
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Which of the following is a solution of x^2+8x= -32
juin [17]

Answer:

X1=-4+4i

X2=-4-4i

Step-by-step explanation:

X^2+8x+32=0

Δ=b^2-4ac=8^2-4(32)=-64<0

X1=(-b-i√Δ) /2a=(-8-8i)/2=-4-4i

X2=(-b+i√Δ) /2a=(-8+8i)/2=-4+4i

3 0
3 years ago
OLA
Rainbow [258]

Answer:

area= hieght times width

Step-by-step explanation:

area= hieght times width

I'm not sure which is which since you provided 3 different numbers but all you need to do is multiply the height and width and you have your answer.

Look to the picture for an example.

8 0
3 years ago
There are 10 seniors and 15 juniors in a gym class. What is the ratio of seniors to total students?
postnew [5]

Answer:

for every 2 seniors there are 3 juniors or 2:3

3 0
3 years ago
Passing through(-1,8) and parallel to the line whose equation is 8x-9y-2=0
notka56 [123]
<h3>Answer:</h3>

y = 8/9x + 80/9

<h3>Step-by-step explanation:</h3>

<u>We are given;</u>

  • Equation of a line as 8x -9y -2 = 0
  • Coordinates (-1,8)

We are required to determine the equation of a line parallel to the given line and passing through a point (-1,8)

<h3>Step 1: Determine the Gradient of the given line </h3>
  • When an equation is written in the form y = mx + c, m is the gradient.
  • Therefore; we could write the equation 8x -9y -2 = 0 in the form of  y= mx + c

9y = 8x -2

y = 8/9x - 2/9

Therefore, the slope, m = 8/9

<h3>Step 2: Determine the equation of the line</h3>
  • We need to know that parallel lines have the same gradient
  • Therefore, the slope of the line in question is 8/9
  • It passes through a point (-1, 8)

We can therefore, determine the equation;

Taking another point, (x,y)

\frac{y-8}{x+1} = \frac{8}{9}

9(y-8) = 8(x+1)

9y - 72 = 8x + 8

 9y = 8x + 8 +72

 9y = 8x + 80

  y = 8/9x + 80/9

Therefore, the equation of the line is y = 8/9x + 80/9

4 0
4 years ago
Midpoint Formula:
Sedaia [141]

The coordinates of the midpoint of the segment joining the two points (0, 2) and (6, 4)​ is (3, 3)

<h3><u>Solution:</u></h3>

Given that two points are (0, 2) and (6, 4)​

To find: coordinates of the midpoint of the segment joining the two points

<em><u>The midpoint of line joining two points is given as:</u></em>

For a line containing two points (x_1, y_1) and (x_2, y_2)

\text {Midpoint}(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

In the given sum, two points are (0, 2) and (6, 4)​

x_{1}=0 ; y_{1}=2 ; x_{2}=6 ; y_{2}=4

Substituting the values in given formula,

\begin{array}{l}{\text {Midpoint}(x, y)=\left(\frac{0+6}{2}, \frac{2+4}{2}\right)} \\\\ {\text {Midpoint }(x, y)=\left(\frac{6}{2}, \frac{6}{2}\right)=(3,3)}\end{array}

Thus the required midpoint is (3, 3)

8 0
3 years ago
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