Answer:
X1=-4+4i
X2=-4-4i
Step-by-step explanation:
X^2+8x+32=0
Δ=b^2-4ac=8^2-4(32)=-64<0
X1=(-b-i√Δ) /2a=(-8-8i)/2=-4-4i
X2=(-b+i√Δ) /2a=(-8+8i)/2=-4+4i
Answer:
area= hieght times width
Step-by-step explanation:
area= hieght times width
I'm not sure which is which since you provided 3 different numbers but all you need to do is multiply the height and width and you have your answer.
Look to the picture for an example.
Answer:
for every 2 seniors there are 3 juniors or 2:3
<h3>
Answer:</h3>
y = 8/9x + 80/9
<h3>
Step-by-step explanation:</h3>
<u>We are given;</u>
- Equation of a line as 8x -9y -2 = 0
- Coordinates (-1,8)
We are required to determine the equation of a line parallel to the given line and passing through a point (-1,8)
<h3>Step 1: Determine the Gradient of the given line </h3>
- When an equation is written in the form y = mx + c, m is the gradient.
- Therefore; we could write the equation 8x -9y -2 = 0 in the form of y= mx + c
9y = 8x -2
y = 8/9x - 2/9
Therefore, the slope, m = 8/9
<h3>Step 2: Determine the equation of the line</h3>
- We need to know that parallel lines have the same gradient
- Therefore, the slope of the line in question is 8/9
- It passes through a point (-1, 8)
We can therefore, determine the equation;
Taking another point, (x,y)

9(y-8) = 8(x+1)
9y - 72 = 8x + 8
9y = 8x + 8 +72
9y = 8x + 80
y = 8/9x + 80/9
Therefore, the equation of the line is y = 8/9x + 80/9
The coordinates of the midpoint of the segment joining the two points (0, 2) and (6, 4) is (3, 3)
<h3><u>Solution:</u></h3>
Given that two points are (0, 2) and (6, 4)
To find: coordinates of the midpoint of the segment joining the two points
<em><u>The midpoint of line joining two points is given as:</u></em>
For a line containing two points
and

In the given sum, two points are (0, 2) and (6, 4)

Substituting the values in given formula,

Thus the required midpoint is (3, 3)